Answer:
Step-by-step explanation:
Let +s+ = the speed of the passenger train
+s+-+20%5D+ = the speed of the freight train
Let +t+ = time in hours for both trains
-------------------------------------
Equation forpassenger train:
(1) +280+=+s%2At+
Equation for freight train:
(2) +180+=+%28+s-20+%29%2At+
------------------------
(1) +t+=+280%2Fs+
Substitute (1) into (2)
(2) +180+=+%28+s-20+%29%2A%28+280%2Fs+%29+
(2) +180s+=+280s+-+5600+
(2) +100s+=+5600+
(2) +s+=+56+
and
+s+-+20+=+36+
The speed of the passenger train is 56 mi/hr
The speed of the freight train is 36 mi/hr
-------------------------------------
check:
(1) +280+=+56%2At+
(1) +t+=+5+
and
(2) +180+=+%28+56-20+%29%2At+
(2) +180+=+36t+
(2) +t+=+5+
OK
I would do Math First just to nock it out the way
Given:
The last year sales = $288,000,000
Company increased its sales from last year to this year by 34%.
To find:
The this year's sales to the nearest million dollars.
Solution:
We have,
The last year sales = $288 million
The company increased its sales from last year to this year by 34%. So,
This year's sales 
Therefore, this year's sales were 386 million dollars or $386,000,000.
In a geometric sequence dividing any term by the term before it yields the common multiplier.
Then x/(x+8) = (3x-8)/x
Solving for x: reduces to x^2-10x +16 factor into (x-2)(x-8)
Then x = 2 or 8
2 produces a sequence of -2, 2, -2 ...
8 produces a sequence of 4, 8, 16 ...
9514 1404 393
Answer:
m = 2k/v
Step-by-step explanation:
Identify the coefficient of m (v/2) and multiply by its inverse (2/v).
(2/v)k = (2/v)m(v/2) . . . . multiply both sides of the equation by 2/v
2k/v = m . . . simplify
m = 2k/v
