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2 years ago

Write the slope and y-intercept of this linear equation: 3y + 6 = –2x

Mathematics

1 answer:

netineya [11]2 years ago

6 0

Answer:

slope = -2/3

y-intercept = -2

Step-by-step explanation:

3y + 6 = -2x

Conver to slope intercept form

3y = -2x - 6

y = -2/3x - 2

Follow the form y = mx + b, so m is the slope and b is the y-intercept

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Can you do this one pls

Virty [35]

Answer:

it is 3.00

Step-by-step explanation:

as you can see first we define the variables

1. the y axis(vertical) represents the cost of peaches while the x axis (the bottom one) represents the number of pounds

2. then we find a place where the line crosses the grid but exactly on the corner of the box

3. when we have found our point which is (2,6) it means that every 2 pounds of peaches is 6 dollars

4. divide 6/2 and you get 3 dollars!

8 0

2 years ago

Read 2 more answers

The amount c in grams of a 100 gram sample of carbon-14 remaining after t years is represented by the equation c= 100 (0.99988)t

tigry1 [53]

Answer: The amount of carbon-14 remaining after 4 years is 99.95 grams.

Step-by-step explanation:

Hi, to answer this question we simply have to substitute t=4 in the equation given and solve for c.

c= 100 (0.99988)^t

c =100 (0.99988)^4

c = 100 x 0.999520086

c= 99.95200864 ≅99.95 grams (rounded)

The amount of carbon-14 remaining after 4 years is 99.95 grams.

Feel free to ask for more if needed or if you did not understand something.

8 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

(x^2−1)(3x−4)(3x+4) what is the product

Andrei [34K]

Answer:

9x^4-25x^2+16

Step-by-step explanation:

(x^2−1)(3x−4)(3x+4)=(*)

(x^2−1)((3x)^2−4^2) =

(x^2 - 1)(9x^2-16)=

x^2*9x^2 - x^2*16 - 1*9x^2 +16=

9x^4-16x^2-9x^2+16=

9x^4-25x^2+16

(*) (A-B)(A+B) =A^2 - B^2

6 0

2 years ago

There are 28 students in Ms. Annand’s class. 25% got an A on their last math quiz. How many students did not receive an A on the

Luden [163]

Answer:

21 students

Step-by-step explanation:

25% of 28 is 7 28-7=21

8 0

2 years ago