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nataly862011 [7]
3 years ago
13

Two students have partially simplified the same expression. Audrey's work: ( x3y−2 22x−5y3 ) 3 = ( x8y−5 22 ) 3 = x24y−15 26 Dav

id's work: ( x3y−2 22x−5y3 ) 3 = x9y−6 26x−15y9
Mathematics
2 answers:
aksik [14]3 years ago
5 0

Answer:

-Aubrey first applied division of like bases by subtracting the exponents.

-Next David will apply the quotient of powers.

-Aubrey's work is correct .

-The correct simplified answer is x^24/64y^15

Crank3 years ago
4 0

Answer:

<h3>-<u>Aubrey first applied division of like bases by subtracting the exponents.</u></h3><h3>-<u>Next David will apply the quotient of powers.</u></h3><h3><u>-Aubrey's work is correct .</u></h3><h3><u>-The correct simplified answer is x^24/64y^15</u></h3>
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100% of what number is 61
Dominik [7]

" 100% " means "the whole thing",
and "is" can be replaced by "is equal to".

You have said "The whole thing of a number is equal to 61."
or
                       "61 is equal to the whole thing of a number."

The only number that 61 can be equal to is 61.

3 0
3 years ago
Read 2 more answers
X/5=2/3=5/y<br><br> 2/3 <br> 4/9<br> 1
Mademuasel [1]
\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
Break the equation into parts;
\frac{x}{5} = \frac{2}{3} ;  \frac{2}{3}= \frac{5}{y}
Solving for x;
\frac{x}{5} = \frac{2}{3}
x=\frac{10}{3}
Solving for y;
\frac{2}{3} = \frac{5}{y} &#10;y= \frac{3*5}{2} &#10;y= \frac{15}{2}
\frac{x}{y} = \frac{10/3}{15/2}
\frac{x}{y} = \frac{4}{15}
5 0
4 years ago
Help me with this one please :(
blsea [12.9K]
C.) 4(2x-6) and 8x-24
8 0
3 years ago
The length of the major axis of the ellipse below is 12, and the length of the red line segment is 4
Alexxx [7]

Answer:

11/2

Step-by-step explanation:

The semi-major axis is 1/2 of the major axis, a, so a = 11/2.

6 0
3 years ago
Read 2 more answers
A circular swimming pool has diameter 60 feet and is centered in a fenced-in square region measuring 80 feet by 80 feet. a concr
borishaifa [10]
If I read the question correctly, the information about the 80x80 fencing and the grass region are all irrelevant information. 

In order to find the area of the side walk we are going to use the formula A=pi(r^2) where r = the radius. The diameter of the pool is 60 feet and the the sidewalk is 5 feet bigger all around meaning we had 5 feet to both sides of this 60 feet giving you an overall diameter of 70 feet (or 60 + 5*2). To find the radius take half of the diameter. 70/2 = 35. 

Now we plug in 35 to the equation. A = Pi(35^2) = 1225pi. Leave your answer like this as we are not finished and will need to round at the end for an accurate answer. This is NOT the end, that number is the area of the sidewalk AND the pool.

The sidewalk is not a full circle, just a border so we now have to find the area of the actual pool and subtract it from this 1225pi for the sidewalk's area. Same formula, Area = pi(r^2). The diameter of the pool is 60 meaning the radius is 30 (or 60/2). Plug into the equation, pi(30^2) = 900pi.

Now do 1225pi - 900pi to get 325pi. Break out your calculator and hit the approximation button. 325pi is approximately 1021.018 if rounded to 3 decimal places.

The area of the 5-foot wide sidewalk encircling the pool is approximately 1021.018 square feet. 


5 0
3 years ago
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