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3 years ago

Answer quickly please

Mathematics

2 answers:

Alex3 years ago

4 0

Answer:

x=6

Step-by-step explanation:

......................

vitfil [10]3 years ago

3 0

Answer:

x=6

Step-by-step explanation:

7x+2y = 48

Let y = 3

7x +2(3) = 48

7x+6 = 48

Subtract 6 from each side

7x+6-6 = 48-6

7x = 42

Divide each side by 7

7x/7 = 42/7

x = 6

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Given f(x)=-x-1f(x)=−x−1, find f(0)f(0).

dalvyx [7]

The value of f(0) is -1

<h3>What is a function?</h3>

A function can be defined as an expression, law or rule that explains the relationship between two variables; a dependent and an independent variable.

Given the function;

f(x)= -x - 1

To determine f(0), we substitute the value of x as 0 in the function

So, we have;

f(0) = -(0) - 1

f(0) = -0 - 1

f(0) = -1

Thus, the value of f(0) is -1

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brainly.com/question/17043948

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7 0

1 year ago

A pressure of a gas at 22°C is 600 mmHg when it occupies 2.5 L. If the gas is compressed to 1.8 L and the pressure changes to 76

zhuklara [117]

APPLICATION OF COMBINED GAS LAW

Combined gas law is a combination of Boyle's, Charles', and Gay-Lussac's Laws that expresses the relationship between pressure, temperature, and volume in a constant amount of gas (moles).

<u>Note:</u>

In solving any problems related to Gas Law, it is important to remember that the standard unit measure for the temperature is always expressed in Kelvin (K). To do so, whatever the given temperature is (either °C or °F) you should convert them first so computation will be efficient.
If the given is in °C, then use the formula $\sf{K = °C + 273.15}$
And if °F, $\sf K = \frac{5}{9} (°F - 32) + 273.15$

So to answer your question, what is the new temperature in K, the new temperature is T2 = 269.176 K or 269.18 K

(Please see attached image for the solution).

6 0

2 years ago

I NEED HELP PLEASE, THANKS! :)

Elena L [17]

Answer:

First option is the right choice.

Step-by-step explanation:

$\frac{1}{\cos \left(x\right)+1}+\frac{1}{\cos \left(x\right)-1}\\\\\frac{\cos \left(x\right)-1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}+\frac{\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{\cos \left(x\right)-1+\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{2cos\left(x\right)}{cos^2\left(x\right)-1}\\\\=\frac{2cos\left(x\right)}{sin^2\left(x\right)}$