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3 years ago

Angles - Question attached maths

Mathematics

1 answer:

svet-max [94.6K]3 years ago

8 0

Answer:

60.4°

Step-by-step explanation:

Angle x = Angle CBG + Angle FEG

(Alternate angles)

Angle x = 34.8 + 25.6

= 60.4°

You might be interested in

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

General term for -13, -11, -9, -7

timurjin [86]

The general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

<h3>Arithmetic progression</h3>

-13, -11, -9, -7

First term, a = -13
Second term = -11

Common difference, d = Second term - first term

= -11 - (-13)

= -11 + 13

= 2

Therefore,

Tn = a + (n - 1)d

Where,

n = number of terms

Tn = a + (n - 1)d

= -13 + (n - 1)2

= -13 - 2n - 2

Tn = -15 - 2n

So therefore, the general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

Learn more about arithmetic progression:

brainly.com/question/6561461

#SPJ1

5 0

2 years ago

If 8^{y}=18^{y+2} what is the value of y?

Nina [5.8K]

Answer:

-8

Step-by-step explanation:

both 8^-8 and 16^-8+2 equal 5.9605

8 0

2 years ago

Read 2 more answers

7 1/4 + 5 3/5= reduced to it's lowest form

Scrat [10]

7 1/4 + 5 3/5
First, you need a common denominator to add the two. 20 will work.
4x5=20, so we have to also multiply 1 by 5.
4x5=20, 1x5=5
5x4=20, so we have to also multiply 3 by 4.
5x4=20, 3x4=12
And now we put the fractions back in.
7 5/20 + 5 12/20
And add them.
7 5/20 + 5 12/20 = 12 17/20
Now, we're supposed to reduce it to its lowest form.
Unfortunately, the fraction cannot be reduced, because 17 is a prime number, meaning there are no factors to it except one and itself.
Therefore, the lowest form of 12 17/20 is 12 17/20
Your answer is B, 12 17/20

4 0

3 years ago

After a long practice, the marching band drank an entire 15 gallon cooler of water. The foot ball team drank 1/3 less than that.

astra-53 [7]

Answer:

the football team drank 10 gallons of water

Step-by-step explanation:

if the football team drank 1/3 less than 15, 1/3 of 15 is 5 so you would then subtract 5 from 15 and you get 10

6 0

3 years ago