Solve each system of equations by using substitution.
x+4y=3
2x-3y=17
2 answers:
Equation 1) x + 4y = 3 Equation 2) 2x - 3y = 17 Multiply ALL of equation 1 by 2 so that both equations have (2x) in it. 1) 2(x + 4y = 3) Simplify. 1) 2x + 8y = 6 2) 2x - 3y = 17 Subtract equations from one another. 11y = -11 Divide both sides by 11. y = -1 Plug in -1 for y in the first equation. x + 4y = 3 x + 4(-1) = 3 Simplify. x - 4 = 3 Add 4 to both sides. x = 7 x = 7, y = -1 ~Hope I helped!~
X+4y=3 subtract 4y from both sides x=3-4y 2x-3y=17, using x found above becomes: 2(3-4y)-3y=17 perform indicated multiplication on left side 6-8y-3y=17 combine like terms on left side 6-11y=17 subtract 6 from both sides -11y=11 divide both sides by -11 y=-1, using this y in x+4y=3 becomes: x+4(-1)=3 x-4=3 add 4 to both sides x=7 So the solution to the system of equation is the point (7, -1)
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