Answer:
Neither linear nor exponential
Step-by-step explanation:
To check for a linear relationship. Find slope.
slope= (-1 - (-2)) / ( 5 - 2) = 1/3
check other points
slope = (1 - (-1) )/ (8 - 5) = 2/3
check more
slope = (4 - 1) / (11 - 8) = 3/ 3 = 1
Nope.
try assuming an exponential:
y = c * (a^x)
-2 = c* (a^2); -2/c = a^2
-1 = c *(a ^5); -1/c = a^5
1 = c * (a^8), 1/c = a^8
(-2/c)^4 = a^8 = 1/c
16/(c^4) = 1/c
c^3 = 16, then a = root (-2/ cube-root(16) )
The change from negative to postive would not work for y = c(a^x)
so...
assume y = a^x + k
-2 = a^2 + k
-1 = a^5 + k
... I would say neither..
We can use vertical opposite angles. Which means the opposite angles where 2 lines intersects is the same.
3x + 50 = 6x - 10 (vert. Opp. Angles)
3x = 6x - 60
-3x = - 60
X = 20°
RS<span> ≅ </span><span>ST is the correct answer</span>
Answer:
Since x is an exponent, y = 15 × 8ˣ represents an exponential function.
9514 1404 393
Answer:
(x, y, z) = (2+44t, 2+14t, 7-20t)
Step-by-step explanation:
One way to write parametric equations for line L is ...
L = P + t·<em>v</em>
where P is the given point and <em>v</em> is the given direction vector. Using that form, we have ...
(x, y, z) = (2+44t, 2+14t, 7-20t)
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If you like, you can remove a common factor of 2 from the coefficients of t.
(x, y, z) = (2+22t, 2+7t, 7-10t)
