Which point is an x-intercept of the quadratic function f(x) = (x

Aahil, James and merav share £90 in the ratio 1:3:5 how much does merav get

Dafna1 [17]

Given: £90 is divided among Aahil, James and Merav in the ratio 1:3:5.

To find: How much Merav gets.

Answer:

Let's assume the shares of each to be 'x'.

This implies that 1x + 3x + 5x = 90.

9x = 90

x = 90/9

x = 10

Substituting this value of x in the ratio,

1 × 10 = 10 [Aahil's share]
3 × 10 = 30 [James' share]
5 × 10 = 50 [Merav's share]

Therefore, Merav gets £50.

Hope it helps. :)

8 0

2 years ago

Hello, please help thank youu!!

uranmaximum [27]

Answer:

36 $\frac{1}{2}$

Step-by-step explanation:

(5 $\frac{1}{2}$ x 3) + (10 ÷ $\frac{1}{2}$ )

(16 $\frac{1}{2}$ ) + (10 ÷ $\frac{1}{2}$ )

(16 $\frac{1}{2}$ ) + (20)

36 $\frac{1}{2}$

7 0

3 years ago

Read 2 more answers

How do I do this I'm am really confused?

MrMuchimi

Since (4y-42) and 2y are opposite angles, they equal to each other which looks like this:

4y-42 = 2y

From there you want to put the y onto one side:

4y-2y-42=0 -----> 2y-42=0

You want to balance the equation out and move the -42 onto the other side so you add it to both sides to get:

2y=42

Then divide both sides by 2 to get:

y= 21

From there you can plug 21 back into the original equation to find each angle.

4(21)-42 = 2(21) ---> 84-42 = 42 ---> 42 = 42

So y = 21 and each angle is 42 degrees

6 0

3 years ago

The current process has a mean of 2.50 and a std deviation of 0.05. A new process has been suggested by research. What sample si

Novay_Z [31]

Answer:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (2) we got:

$n=(\frac{1.96(0.05)}{0.02})^2 =24.01$

So the answer for this case would be n=25 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=0.05$ represent the population standard deviation

n represent the sample size (variable of interest)

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

And on this case we have that ME =0.02 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (2) we got:

$n=(\frac{1.96(0.05)}{0.02})^2 =24.01$

So the answer for this case would be n=25 rounded up to the nearest integer

7 0

3 years ago

5 1/3 - 3 2/6 (then simplify)

Reil [10]

5 1/3 - 3 2/6 simplify is 2.

6 0

2 years ago

Read 2 more answers

Which point is an x-intercept of the quadratic function f(x) = (x - 4)(x + 2)?