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sveta [45]
3 years ago
10

Find the speed of a race car if it travels 5 miles in 2 minutes and 30 seconds

Mathematics
1 answer:
Tomtit [17]3 years ago
4 0
You first convert the 2 minutes and 30 seconds to 150 seconds.

Then, you take the 150s÷5m to get the number of seconds per mile.

The answer is 30s/m
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Supply the missing reasons to complete the proof.
MAXImum [283]

Answer:

3. ASA

4. Corresponding sides of congruent triangles are congruent

Step-by-step explanation:

I marked this in the attached image. ∠B ≅∠E, ∠ACE ≅ ∠DCE, and the side between them BC ≅ EC, so the the triangles ΔACB and ΔDCE are congruent by ASA.

If the triangles are congruent, then all corresponding angles and sides are also congruent.

7 0
2 years ago
You pay $80 for a game system. The monthly rental fee for games
hichkok12 [17]

Answer:

m=9

Step-by-step explanation:

12m+80=188

subtract 80 from both sides to get the m alone.

12m+80-80=188-80

12m=108

divide both sides by twelve.

12m/12=108/12

m=9

6 0
2 years ago
Read 2 more answers
Find the area of the shaded portion in the equilateral triangle with sides 6. Show all work for full credit. (Hint: Assume that
Vadim26 [7]
So... if you notice the picture below

each circle, has their central angle at the vertex of the triangle
that simply means, 3 circles with a radius of 3, overlapping the triangle

now, the area in the middle, the shaded one, will be, the whole area of the triangle MINUS those 3 circle sectors

hmmmm each sector has 60°, that means, all three of them will then be 60+60+60 or 180°, so the area of those three sectors, can be combined into a 180° sector, well, hell, 180° is really half a circle

so.... the area of those three sectors of 60° each, all three combined, is the same area of half a circle with a radius of 3

so    \bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\textit{length of one side}\\\\
-----------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad r=radius\\\\
\textit{area of half a circle}\\\\
A=\cfrac{\pi r^2}{2}\\\\
-----------------------------\\\\

\bf \textit{now, let us use the side of 6, and radius of 3}
\\\\\\

\begin{array}{clclll}
\cfrac{6^2\sqrt{3}}{4}&-&\cfrac{\pi 3^2}{2}\\
\uparrow &&\uparrow \\
triangle's&&semi-circle's
\end{array}\impliedby \textit{area of shaded area}\\\\
-----------------------------\\\\
\boxed{\cfrac{36\sqrt{3}}{4}-\cfrac{9\pi }{2}}

you can, add the fractions if you want, or leave them like that, or get their difference by using their decimal format

8 0
3 years ago
Read 2 more answers
Through what angle does the minute hand of a clock turn in 12 minutes of time?
harina [27]
A method to solve such problems is to consider the rate of change of the angle in degrees per minute. The hour hand of a normal 12-hour analogue clock turns 360° in 12 hours (720 minutes) or 0.5° per minute. The minute hand rotates through 360° in 60 minutes or 6° per minute.
6 0
4 years ago
In a group of students, the ratio of girls to boys is 3 to 2. If there are 15 girls, how many total students are there? 10 20 25
Ksju [112]

Your answer is 25 students in total

4 0
3 years ago
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