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madreJ [45]
2 years ago
15

In the expression (ax+b)*(cx^2+dx+e), find two set of values of a,b,c,d and e so that the coefficient of x^3and x terms after ex

pansion are 4and 10 respectively.
Mathematics
1 answer:
Brilliant_brown [7]2 years ago
7 0

Answer:

2, 0, 2, 3, 5

1, 2, 4, 0, 5

Step-by-step explanation:

(ax + b)(cx² + dx + e)

acx³ + adx² + aex + bcx² + bdx + be

2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0

4x³ + 6x² + 10x

a = 2

b = 0

c = 2

d = 3

e = 5

1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10

4x³ + 8x² + 10x + 10

a = 1

b = 2

c = 4

d = 0

e = 5

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Julli [10]
Well, we can use some simple addition, okay? So if Ally has 7 cubes, and Greg has four, we can use the equation: x+y = ?, so 7 + 4 = 11. x and y don't mean anything in this scenario, but I just used them as variables. I hope this helps! :)
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4 years ago
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Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2
kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}

Multiply -y+x=2 by 2:  -2y+2x=4

\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}

so adding

-2y+2x=4

+

\underline{2y-2x=7}

0=11

so the system of equations becomes

\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0
3 years ago
What is the greatest common factor of 200 and 140 
Tanzania [10]
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The answer is




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4 years ago
a D.J. at a school dance plans to play dance music for 2 hours. she has 20 requests for songs. Each song plays for 3 1/2 minutes
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tada

answer is 50

4 0
3 years ago
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