From every 6 candle stubs ? One new candle can be made. You have 401 stubs , how many candles can be made in total ?

Mathematics

1 answer:

Mrrafil [7]4 years ago

3 0

401 ÷ 6 = 66.83 so id probably round it up to 66

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Tính : a) (a+b+c)^2 b) (a-b-c)^2 c) (a+b-c)^2 d) (a-b+c)^2

LiRa [457]

Answer:

a.) a² + b² + c ² + 2ab + 2ac + 2bc

b.) a² + b² + c² - 2ab - 2 ac + 2bc

c ) a² + b² + c² + 2ab - 2ac - 2bc

d.) a² + b² + c² - 2ab + 2ac - 2bc

Step-by-step explanation:

Use ( a + b + c )² = a² + b² + c² + 2 × ab + 2 × ac + 2 × bc to expand all these expression

a) ( a + b + c )²

= a² + b² + c² + 2 × ab + 2 × ac + 2 × bc

= a² + b² + c ² + 2ab + 2ac + 2bc

b.) ( a - b - c )

= a² + ( - b )² + ( - c)² + 2a ( -b ) + 2a(-c) + 2(-b)(-c)

= a² + b² + c² - 2ab - 2 ac + 2bc

c.) ( a + b - c )²

= a² + b² + ( -c)² + 2ab + 2a ( - c) + 2 b( -c)

= a² + b² + c² + 2ab - 2ac - 2bc

d.) (a - b + c ) ²

= a² + ( -b)² + c² + 2a(-b) + 2ac + 2c( -b)

= a² + b² + c² - 2ab + 2ac - 2bc

3 0

3 years ago

Suppose cos(O) = 12/13, Quadrant I. Find sin(O). A:13/12 B:5/13 C:13/5 D:5/12

noname [10]

Answer:

B: 5/13

Step-by-step explanation:

pythagoras theorem: a^2 + b^2 (sides) = c^2 (hypotenuse)

a^2 + 12^2 = 13^2

a^2 + 144 = 169

a^2 = 25

a = 5

sin = opp/hyp

sin 5/13

Hope this helps

7 0

3 years ago

The equation 50=36.50+0.10m represent the additional number of messages roboerto can send with a budget of $50 .solve the equati

charle [14.2K]

Answer :
M = 135

Step by Step Explanation :
See the photo attached :) it’s kinda hard to explain in words but you cancel out the 36.50 by subtracting it on both sides, and then the equation becomes 13.50 = 0.10m. Since we have to get the m by itself, you cancel out the 0.10 by subtracting on both sides, and it leaves you with 135 = m

(Ignore my messy handwriting on a post it :3)

I hope this helped! If u have any questions feel free to comment on this!