All categories

3 years ago

Classify the reaction between zinc and acetic acid and explain, in general terms,

Chemistry

1 answer:

Nitella [24]3 years ago

8 0

Answer:

The reaction between zinc and acetic acid is a single-replacement reaction. During this type of reaction basically one element replaces one compound.

The balanced equation for the reaction between zinc and acetic acid is

Zn(OH)_2 +2CH_3 COOH ----> Zn(CH_3COO)_2+2H 2O

Or this might help too!

Balanced Chemical Equation

A balanced chemical equation is defined as the chemical equation which has an equal number of atoms on both sides of the reaction arrow. A balanced chemical equation is based on the law of conservation of mass.

Answer and Explanation:

Below is the reaction between acetic acid and Zinc:

Z n + 2 H C 2 H 3 O 2 → Z n ( C H 3 C O O ) 2 + H 2

This reaction is an example of a reaction between an acid and a metal. When an acid reacts with a metal, salt, and Hydrogen gas forms. The Hydrogen gas formed here can be tested as it burns with a POP sound.

<h2>Hope this helps!!!</h2>

You might be interested in

Which substance can't be broken down by chemical means?

irina1246 [14]

Antimony cannot be broken down by chemical means because it is an element, a principle building block of matter. All other choices are compounds, which can be separated if put through enough stress to break the bonds between the atoms.

5 0

4 years ago

2<br> 1. Biology is the study of

Inessa05 [86]

Biology is the study of life

7 0

4 years ago

Give the half equation to show what happens to oxygen when it is rusting

ycow [4]

Answer:

½O 2 + 2e - + H 2O → 2OH.

Explanation:

Redox reactions - Higher

In terms of electrons:

oxidation is loss of electrons

reduction is gain of electrons

Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:

iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-

oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-

iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-

3 0

3 years ago

Determine the empirical formula of a compound containing 63.50 % silver, 8.25 % nitrogen, and the remainder oxygen.

iogann1982 [59]

Answe AgNO₃

1:1:3 ratio

8 0

3 years ago

2. How many moles of hydrogen atoms are there in 154 mL of 0.18 M H2SO4? Write your

katrin [286]

2. 0.05544 moles of hydrogen atom are present in 154 mL 0.18 M solution of H2SO4.

3. 15.2506 heat in Joules is absorbed by 150.0 mL of pure water that is heated from 21.2°C to 45.5°C.

4. 0.75 M is the concentration of Na+ ions in 25.0 mL of 1.50 M NaOH is reacted with 25.0 mL of 1.50 M HCI

Explanation:

Number of moles of H2SO4 can be calculated by the given volume and molarity from the formula:

molarity = $\frac{number of moles}{volume of teh solution}$

number of moles = molarity × volume of the solution of H2SO4

number of moles = 0.18 × 0.154 litres

= 0.02772 moles of H2SO4.

Since 1 mole of H2SO4 contains 2 moles of hydrogen

so, 0.02772 moles of H2SO4 will have x moles

$\frac{1}{2}$ = $\frac{0.0272}{x}$

2 × 0.02772 = x

0.05544 moles of hydrogen atom are present in 154 mL 0.18 M solution of H2SO4.

3. The heat absorbed is calculated from the formula:

ΔH = cp × m × ΔT ( ΔT = change in temperature in Kelvin, m in kg, cp= specific heat of water)

putting the values in formula:

ΔH = 4.184 × 0.15 × ( 318.65-294.35)

= 4.184 × 0.15× 24.3

= 15.2506 Joules of heat is absorbed.

4. The concentration of Na+ ions

the balanced equation is

NaOH + HCl⇒ NaCl + H20

from one mole of NaCl 1 mole of NaCl i.e one 1 mole of Na+ ions is formed.

number of moles of NaOH is calculated by the formula:

Molarity = $\frac{number of moles}{volume of the solution}$

number of moles = 0.025L × 1.50M

= 0.0375 moles of NaOH

so 1 mole of NaOH produces 1 mole of Na= ions

hence, 0.0375 moles produces x moles of Na+ ions

$\frac{1}{1}$ = $\frac{0.0375}{x}$

moles of Na+ is produced.

concentration of NaOH in 50 ml solution because NaOH and HCl of 25 ml reacted.

applying the molarity formula from above

Molarity = $\frac{0.0375}{0.05}$

= 0.75 M

6 0

3 years ago