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Pani-rosa [81]
3 years ago
15

Which of these is the lowest subgroup? kingdom, order, genus, or species.

Chemistry
2 answers:
olga55 [171]3 years ago
6 0
The correct answer is species

Aleksandr [31]3 years ago
5 0

Answer:

Species

Explanation:

The acronym, DKPCOFGS; Gives you an explanation of the subgroups highest - lowest.

Did

King

Phil

Come

Over

For

Good

Spagettii

Spagettii is species in the acronym

Enjoy your test :D

-Snooky

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Naming Compounds Test Review Practice Name the following ionic compounds: NH4Cl _____________________________________ Fe(NO3)3 _
Mariulka [41]

Answer :

The name of NH_4Cl is ammonium chloride.

The name of Fe(NO_3)_3 is iron(III) nitrate.

The name of TiBr_3 is titanium(III) bromide.

The name of Cu_3P is copper(I) phosphide.

The name of SnSe_2 is tin(IV) selenide.

The name of GaAs is gallium arsenide.

The name of Pb(SO_4)_2 is lead(IV) sulfate.

The name of Be(HCO_3)_2 is beryllium hydrogen carbonate.

The name of Mn_2(SO_3)_3 is manganese(III) sulfite.

The name of Al(CN)_3 is aluminium cyanide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) NH_4Cl

It is an ionic compound because it is formed by the combination of one polyatomic cation (ammonium ion) and anion (chloride ion). The charge on ammonium ion is (+1) and the the charge on chloride ion is (-1).

Thus, the name of NH_4Cl is ammonium chloride.

(b) Fe(NO_3)_3

It is an ionic compound because it is formed by the combination of one polyatomic anion (nitrate ion) and cation (iron ion). The charge on iron ion is (+3) and the the charge on nitrate ion is (-1).

Thus, the name of Fe(NO_3)_3 is iron(III) nitrate.

(c) TiBr_3

It is an ionic compound because it is formed by the combination of titanium cation and bromide anion. The charge on titanium is (+3) and the the charge on bromide ion is (-1).

Thus, the name of TiBr_3 is titanium(III) bromide.

(d) Cu_3P

It is an ionic compound because it is formed by the combination of copper cation and phosphorous anion. The charge on copper is (+1) and the the charge on phosphorous ion is (-3).

Thus, the name of Cu_3P is copper(I) phosphide.

(e) SnSe_2

It is an ionic compound because it is formed by the combination of tin cation and selenium anion. The charge on tin is (+4) and the the charge on selenium ion is (-2).

Thus, the name of SnSe_2 is tin(IV) selenide.

(f) GaAs

It is an ionic compound because it is formed by the combination of gallium cation and arsenic anion. The charge on gallium is (+3) and the the charge on arsenic ion is (-3).

Thus, the name of GaAs is gallium arsenide.

(g) Pb(SO_4)_2

It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfate ion) and cation (lead ion). The charge on lead ion is (+4) and the the charge on sulfate ion is (-2).

Thus, the name of Pb(SO_4)_2 is lead(IV) sulfate.

(h) Be(HCO_3)_2

It is an ionic compound because it is formed by the combination of one polyatomic anion (hydrogen carbonate ion) and cation (beryllium ion). The charge on beryllium ion is (+2) and the the charge on hydrogen carbonate ion is (-1).

Thus, the name of Be(HCO_3)_2 is beryllium hydrogen carbonate.

(i) Mn_2(SO_3)_3

It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfite ion) and cation (manganese ion). The charge on manganese ion is (+3) and the the charge on sulfite ion is (-2).

Thus, the name of Mn_2(SO_3)_3 is manganese(III) sulfite.

(j) Al(CN)_3

It is an ionic compound because it is formed by the combination of one polyatomic anion (cyanide ion) and cation (aluminium ion). The charge on aluminium ion is (+3) and the the charge on cyanide ion is (-1).

Thus, the name of Al(CN)_3 is aluminium cyanide.

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Answer:

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Explanation:

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S-0.498986433806336 (0.5)

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B-2.959948200906496 (3)

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D) If only 6.6 grams of water are produced, what is the percent yield?

Write out the balanced equation:

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Then, determine the limiting reagents:

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45.8 grams of O2/32 g/mol of O2 = 1.4 mol

0.46 mol of C2H6/2 = 0.23

1.4 mol of O2/7 = 0.20

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<em>We can setup a proportion;</em>

7/6 = 0.23/x

0.196 = x

So, 0.196 mol of water will be produced.

How many grams of water will be produced in the reaction?

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