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3 years ago

11

Why do we have to change an improper fraction to a mixed fraction

2 answers:

pogonyaev3 years ago

6 0

Answer:

My I don't know it is stupied!

Step-by-step explanation:

777dan777 [17]3 years ago

6 0

Answer:

Step-by-step explanation: Because improper is incorrect and mixed fraction actual is real.

HOPE I HELPED YOU

WOOOAH

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Find x from given equations sin30 + 2 cot^2 30 + x cos^2 30= 8+ tan^2 45 + cos 60

julia-pushkina [17]

Answer

1/2+2×(sqrt3)^2+x.(sqrt3/2)^2=8+1^2+1/2

1/2+2×3+x.3/4=8+1+1/2

1/2-1/2+6+x.3/4=9

x.3/4=9-6

x.3×4=3

x.3=3×4

x.3=12

x=12/3

x=4.

so, the value of x is 4.

hope it helps you.

4 0

3 years ago

write the particular equation of this transformed sine graph. assume that the horizontal shift is 1 unit to the right. (hint: tr

Goryan [66]

We are given the graph of sine function.
First, we get the amplitude
A = [6 - (-2)] / 2
A = 4

Next, we determine the period and b
T = 4 - 0 = 4
b = 2π / T
b = π/2

The original sine function was
y = 4 sin πx/2

After the transformation, the equation now is
y = 4 sin [π(x+2)/2] + 2

4 0

3 years ago

Read 2 more answers

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

Solve by elimination<br> 5x+4y = 12<br> 3x - 3y = 18<br><br> Please help solve and provide steps.

SOVA2 [1]

First you solve for y.
5x+ y= 12 so Y= 12-5x
And plug it into the next equation
3x- 3(12-5x) = 18
Distribute
3x-36+15x=18
Add 36 to both sides
3x+ 15x= 54
18x= 54 ... divide
x= 3
And you can plug in x to solve for Y
5(3) + y = 12
15+ y = 12 ...subtract 15 from both sides
y= -3

4 0

3 years ago

Read 2 more answers

PLS ANSWER DUE LATER TODAY!!!

Readme [11.4K]

Answer:

1) y= 2x-4

2) y= 2/3 - 3

3) y=1/2x+2

4) y=-4x-4

Step-by-step explanation:

all you basically has to do is is subtract the x to isolate the y and if the y and if the y still has a number by it you use it to decide it

6 0

3 years ago