Answer:
Step-by-step explanation:
[−1,1] and [0, 
]
hope this helped :)
Step-by-step explanation:
everything can be found in the picture
Answer:
![\left[\begin{array}{cc}x&y&-2&-9&0&-1&2&7&4&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%26-2%26-9%260%26-1%262%267%264%2615%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given
Required
Create a function table for inputs -2, 0, 2 and 4
When x = -2
When x = 0
When x = 2
When x = 4
So, the table is:
Algebraically, find the zeroes (x-intercepts) of each quadratic .A quadratic function is shown in the table below Which of the ... Consider the quadratic function whose equation is f(x) = x2 + 2x -8. ... y = 4x – 5 and y = 2x2 – 5x-10 ..X-4=0. Xx2zo. Factored. +2. ) (x-ulzo. ) who form. X-4x+3x-&co x²-2x 8-0
Answer:
the probability is 4/9 (44,44%)
Step-by-step explanation:
Assuming that each point inside the square is equally probable, then the probability is uniformly distributed in area of the square. Thus
probability = area where condition is true / total area of the square
for a circle of radius 1/3 inside the square ,the area where this condition is satisfied is a square with sides 1-1/3 = 2/3 , thus
probability = (2/3)²/1² = 4/9
thus the probability is 4/9 (44,44%)
