The amount that Jimmy paid for his meals the four days, $6.45, $21.38, $1.99, $7.99, $16, $0, $7.99, $18.95, $4.30, $10.35, $18.
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Answer:
$7.99
Step-by-step explanation:
Arrange numbers in numerical order: $0, $1.99, $4.30, $6.45, $7.99, $7.99, $10.35, $16, $18.20, $18.95, $21.38.
Count how many numbers you have, 11.
11 is an odd number so, the number in the middle of the data set is the median.
Final answer: $7.99 is the median.
Answer:
Step-by-step explanation:
<u>Since all graphs pass throught the origin, they all have the form of:</u>
- y = ax², where a- coefficient
The coefficient of each graph's equation can be calculated based on the given pairs of points.
Each of them calculated for you and attached below.
Answer:
(3, -3)
Step-by-step explanation:
The vertex of the most general absolute value function is y = |x|, whose vertex is at (0, 0). Focusing on the " |x - 3| " tells us that the graph of y = |x| is moved 3 units to the right. Next, focusing on the " -3 " as it tells us that the resulting graph is shifted 3 units down. Thus, the vertex of g(x)=|x-3|-3 is at (3, -3).
A sector is a <u>part</u> of a <u>circle</u> that is formed by two<em> radii,</em> and an <em>arc</em>. So that the length of the <em>safety railing</em> required is 31.4 feet.
A sector is a <em>part </em>of a <u>circle</u> that is formed by two <u>radii</u>, and an <u>arc</u>, thus forming a <em>central</em> angle.
Thus the required <em>length</em> of safety railing can be considered as the <u>arc</u> of the<em> sector. </em>
So that;
<u>length</u> of an <u>arc</u> = (θ /
) * 2
r
where θ is the <u>measure</u> of the <em>central angle</em> of the sector, and r is the <u>radius</u> of the sector.
From the given question, θ = 45°, and r = 40 feet.
So that,
<u>length</u> of the<em> safety railing </em>= (45° /
) * 2 * 3.14 * 40
= 0.125 * 2* 3.14* 40
<u>length</u> of <em>safety railing</em> = 31.4
Therefore, the <u>length</u> of the <em>safety railing</em> required is 31.4 feet.
For more clarifications on the length of an arc, visit: brainly.com/question/2005046
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