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san4es73 [151]
3 years ago
8

What would 2300 divided by 330 times 3 epuals what ?

Mathematics
2 answers:
Amanda [17]3 years ago
3 0

Answer: 23

Step-by-step explanation:

Yanka [14]3 years ago
3 0

Answer:20.90

Step-by-step explanation:

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Help! Ill mark you as brain! 15 points!
Alina [70]

Answer:

35 in²

Step-by-step explanation:

The irregular shaped can be divided into two squares and one rectangle, so the area will be the additions of the area of the squares and the rectangle

area of square A = L *B = 3 *3 = 9in²

area of square B = L * B = 4*4 = 16in²

area of rectangle C = L * B = 5 *2 = 10in²

th area of the irregular shape = 9 in² + 16 in² + 10 in² = 35 in²

4 0
3 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
Which of the following values has 4 significant figures?
Vlad1618 [11]

Answer:

А. 13.07

Step-by-step explanation:

Significant figures are the number of digit from a number that have meanings. The higher the significant figures of a number, the higher its accuracy will be.  The only non-zero number will be count as significant figures unless the zero is between two non-zero numbers like 13.07, the zero placed between 3 and 7. Some number also doesn't count as significant figures like the leading zero.

All other option just shows 3 significant numbers, so the answer is 13.07

6 0
3 years ago
Find the slope of the line through the pair of points.<br> (13, 5) and (3,5)
Ronch [10]

Answer: 0

Step-by-step explanation:

So the slope of a line is equal to rise over run, or the change in x over the change in y. We can solve for the change in x and the change in y by finding their differences. For the math, we use the formulas y2 - y1/x2 - x1. Filling in this formula we get, (5-5)/(3-13), which is equal to 0/10. Because 0 divided by anything is 0, the answer here is 0.

8 0
3 years ago
Cos (a + 60 ) + Cos (a-60)​
Nadusha1986 [10]

Answer:

the answer is 0.9988747935

hope that works!!

8 0
3 years ago
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