The equation of line parallel to
and containing the point(-10,-3) is 
Step-by-step explanation:
We need to write the equation parallel to and containing the point(-10,-3)
The standard form of point slope equation is:
where m is slope and b is y-intercept
Comparing the given equation with standard form the slope is m= -1/5
Since the lines are parallel the slope of new line is m = -1/5
Now finding b (y-intercept)
Using slope m=-1/5 and point (-10,-3)
So, b= -5 and slope = -1/5 the equation of new line is:
So, The equation of line parallel to and containing the point(-10,-3) is
Keywords: Point Slope form
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(12 x 16) = 192 + 8 = 200
Therefore the answer is 200 which when divided by 12 gives a quotient of 16 and a remainder of 8.
step 1
Find the measure of angle 1
REmember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle ABC
90+58+<1=180
148+<1=180
<1=180-148
<1=32 degrees
step 2
Find the measure of angle 2
we know that
<2=<1 -----> bt vertical angles
so
<2=32 degrees
step 3
Find the measure of angle 3
REmember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle CDE
32+108+<3=180
140+<3=180
<3=180-140
<3=40 degrees
So just use a calculator but here goes
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729
and 3^7 is 2187 which is excluded
Quadratic equations CAN be used to solve word problems so the answer to your question is false
