The 2nd and 3rd terms in the following algebraic sequence are x and y. Write down algebraic expressions for the first, fourth an
d fifth terms.
1 answer:
Answer:
see explanation
Step-by-step explanation:
To obtain a term in the sequence add the previous 2 terms, that is
=
+
← in general terms
(a)
Given 1 4 5 9 14
Then the next 2 terms are 9 + 14 = 23 and 23 + 14 = 37
(b)
Given a₄ = 30 and a₅ = 49 , then
a₃ = 49 - 30 = 19
a₂ = 30 - 19 = 11
a₁ = 19 - 11 = 8
Sequence is 8 11 19 30 49 ....
(c)
Given a₂ = x and a₃ = y , then
a₁ = y - x
a₄ = a₃ + a₂ = y + x
a₅ = a₄ + a₃ = y + x + y = 2y + x
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Answer:
(x, y) = (3, 26)
Step-by-step explanation:
I like to solve systems of equations like this by graphing. A graphing calculator easily shows the solution for both x and y.
(x, y) = (3, 26)
__
As an alternative, here, the equations can be subtracted.
y = f(x)
y = g(x)
0 = f(x) - g(x) . . . . subtract the second equation from the first
0 = 11x -7 -(3x +17)
0 = 8x -24 . . . . simplify
0 = x -3 . . . . . . .divide by 8
3 = x
Now, we can substitute into either equation:
y = g(x) = 3(3) +17 = 26
The solution is (x, y) = (3, 26).
