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3 years ago

How would I solve this?

Mathematics

1 answer:

zvonat [6]3 years ago

4 0

Use Pythagorean Theorem which states that in a right triangle:

$a^2+b^2=c^2$ , where a and b are the legs, and c is the hypotenuse.

$24^2+10^2=x^2$

Take the square root of both sides to solve for x.

$x = \sqrt{676} = 26$

The answer is 26.

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That's as much of an answer as you can get.

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2 years ago

Atriangular sign has an area of a square feet. the width of the sign is 5 feet. which equation represents h, the height of the s

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Answer:

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Step-by-step explanation:

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2 years ago

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Your brother has $2000 saved for a vacation his airplane ticket is $637 write and solve an Inequality to find out how much he ca

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3 years ago

Salama makes fruit baskets with oranges and bananas.

vovangra [49]

The ratio for problem is:

oranges : bananas = 9 : 6 or oranges : bananas = 6 : 4

Solution:

Given that, Salama makes fruit baskets with oranges and bananas

She uses between 8 and 16 oranges and bananas in a ratio of 3 oranges to 2 bananas

Given ratio is:

Ratio of orange to bananas = 3 : 2

They add up to 5 fruits, so some possible values are 5, 10, 15 , 20, 25, etc

But we need a value between 8 and 16 oranges and bananas

So we can choose 15 or 10

Now let us choose 15 and solve

Let the oranges be 3x

Let the bananas be 2x

Therefore,

3x + 2x = 15

5x = 15

x = 3

Thus oranges = 3x = 3(3) = 9

Bananas = 2x = 2(3) = 6

Thus the ratio for problem is:

oranges : bananas = 9 : 6

Similarly solve for 10

3x + 2x = 10

5x = 10

x = 2

Thus oranges = 3x = 3(2) = 6

Bananas = 2x = 2(2) = 4

Thus the ratio for problem is:

oranges : bananas = 6 : 4

8 0

3 years ago

The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard

arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ $1^s^t$ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have: $\mu=5\ ft$ $\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1$

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒ $2^n^d$ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1$

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒ $3^r^d$ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2$

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒ $4^t^h$ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3$

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0

3 years ago