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sineoko [7]
3 years ago
6

Solve the equation. 8x= 72

Mathematics
2 answers:
BigorU [14]2 years ago
6 0

Answer:

X=9

You divide 8 in each side and you will get x=9

Step-by-step explanation:

mars1129 [50]2 years ago
4 0

Answer:

x = 9

Step-by-step explanation:

8x = 72

Divide each side by 8 to isolate x

8x/8 = 72/8

x = 9

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Geometry homework! help
Bogdan [553]

Answer:

cos∠ABC = 12/15 = 0.80

tan∠ABC = 9/12 = 0.75

sin∠ACB = 12/15 = 0.80

cos∠ACB = 9/15 = 0.60

tan∠ACB = 12/9 = 1 1/3

Step-by-step explanation:

Find the Adjacent, Opposite, or Hypotenuse angles to the angles in the picture and fill them into the given fraction.

cos∠ABC = Adjacent/Hypotenuse = 12/15 = 4/5 = 0.80

tan∠ABC = Opposite/Adjacent = 9/12 = 3/4 = 0.75

sin∠ACB = Opposite/Hypotenuse = 12/15 = 4/5 = 0.80

cos∠ACB = Adjacent/Hypotenuse = 9/15 = 3/5 = 0.60

tan∠ACB = Opposite/Adjacent = 12/9 = 1 1/3 (1 1/3 in decimal form is 1.3 with a line on top of 3 (Bar on top of 3))

8 0
2 years ago
To get from your house to class you walk east 579 feet. after class you walk south west 965 feet to meet your friends at lunch.
svlad2 [7]
You formed a right-angled triangle. I drew this out at first, but you can double check it as 579² + 772² = 965², which is the rule for a right-angled triangle. I hope this helps!
3 0
3 years ago
Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
If a projectile is fired straight upward from the ground with an initial speed of 64 feet per
natali 33 [55]

Answer:

h = 64 feet

Step-by-step explanation:

If you graph the function you see that 64 feet is the maximum of the parabola so this is the max height that the projectile reaches.

3 0
3 years ago
Wright the ratio 4.5 : 2.35 in the form n : 1
sergeinik [125]

Answer:

\frac{9}{47}: 1

Step-by-step explanation:

you can divide both sides by 2.35 to get the right side to be 1:

4.5: 2.35\\\frac{9}{47}: 1

6 0
2 years ago
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