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NNADVOKAT [17]
3 years ago
5

N equation is shown below:

Mathematics
1 answer:
QveST [7]3 years ago
7 0
12x -6 = 1 then 12x =7
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792m rounded to 2 significant figures
deff fn [24]

Answer:

790 with a dash over the 9

Step-by-step explanation:

8 0
3 years ago
When the turnpike littered the toll, traffic increased from 1,500 cars per day to 2,700
umka21 [38]

Answer:

  80%

Step-by-step explanation:

The percentage change between two numbers can be calculated as ...

  percentage change = ((new value)/(old value) -1) × 100%

  = (2700/1500 -1) × 100% = (1.80 -1) × 100% = 80%

Traffic volume increased 80%.

6 0
3 years ago
What is Q1 AND Q3 AND IQR OF THE NUMBERS<br>2,12,52,33,8,14
Sedaia [141]
It is 25.

Q1 is 8
Q3 is 33
7 0
2 years ago
Read 2 more answers
Can someone help me with this? Please this would mean so much.
Paha777 [63]

Answers:

x = angle MLN = 35 degrees

angle FLJ = 55 degrees

=================================================

Explanation:

This problem is fairly tricky if you're not sure what to look for. A slight clue is that they've marked a red point that strangely doesn't have a label on it. It's a fairly small point but it's definitely there if you look closely. While this point's location isn't exactly what we want, we're fairly close. Start at point L and draw a ray through the center point P. Ray LP will intersect the circle at point A, as shown in the diagram below.

From here, draw segments FA and MA. Now notice that inscribed angle LMF = 55 and inscribed angle FAL both subtend the same arc. The term "subtend" basically means "cut off". This arc that the inscribed angles subtend is minor arc FL. A minor arc is where you travel the shorter path around the circle, which indicates its measure is less than 180 degrees.

Since inscribed angles LMF and FAL subtend the same minor arc, this makes the inscribed angles to be congruent.

In short: angle FAL is 55 degrees

----------------------

Segment LA goes through the center P. Through Thales theorem, we know that inscribed angle LFA is 90 degrees. Consequently, we can determine that inscribed angle FLA is 90-55 = 35 degrees.

Segment JL is tangent to the circle, meaning that angle ALJ is 90 degrees. So angle FLJ is 90-35 = 55 degrees.

It's not a coincidence that angle FLJ, angle FAL, and angle LMF are the same measure.

----------------------

We found that angle FAL was 55 degrees. Applying Thales theorem again shows that angle MAF is 90 degrees. Therefore, angle LAM is 90-55 = 35 degrees.

Focus now on triangle LMA. This is also a right triangle (Thales Theorem). The upper acute angle we found was angle LAM = 35, so the lower acute angle is ALM = 55.

Then we can find angle MLN = (angle ALN) - (angle ALM) = 90 - 55 = 35

In short, angle MLN = 35 degrees

Similar to the previous section, it is not a coincidence that angles LFM, LAM and MLN are the same measure.

------------------------

As an alternative, since we know angle FLJ = 55, and angle FLM is 90 degrees, this means...

(angle FLJ)+(angle FLM) + (angle MLN) = 180

55 + 90 + angle MLN = 180

145 + angle MLN = 180

angle MLN = 180 - 145

angle MLN = 35 degrees

7 0
2 years ago
The school that Imani goes to is selling tickets to the annual dance competition. On the first day of the ticket sales the schoo
Tatiana [17]

Answer:

The adult and the child ticket are both 8 dollars

Step-by-step explanation:

x =adult ticket price

y = child ticket price

I will assume you forget to put that they sold 2 child tickets on the second day

7x+5y=96 and 3x+2y= 40

I will use elimination.  Multiply the first equation by 2 and the second equation by -5 to eliminate y

2(7x+5y)=96*2

14x + 10y = 192

The second equation

-5(3x+2y)= 40*-5

-15x -10y = -200

Add the equations together

14x + 10y = 192

-15x -10y = -200

------------------------

-x = -8

Multiply by -1

x = 8

Now we need to find y

3x+2y= 40

3(8) +2y = 40

24+2y = 40

Subtract 24 from each side

24-24 +2y = 40-24

2y = 16

Divide by 2

2y/2 =16/2

y =8

The adult and the child ticket are both 8 dollars


8 0
3 years ago
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