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4 years ago

If 2 and 4 each divide q without remainder which of the following must q divide without remainder

Mathematics

2 answers:

Contact [7]4 years ago

8 0

<span>i would say that it is because the answer cannot be determined from the information given.</span>

Abid 3 years ago

0 0

Yar ma ny

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Beginning drivers soon learn that bringing an automobile to a stop requires greater distances for higher speeds. A formula that

BaLLatris [955]

The formula for the stopping distance in feet is

$d=1.1v+0.055v^2$

where $v$ = Speed of the car in miles per hour.

The stopping distance for the car traveling at 15 mph is

$d=1.1\times 15+0.055\times 15^2\\\Rightarrow d=28.875\approx 29\ \text{feet}$

The stopping distance for the auto traveling at 15 mph is $29\ \text{feet}$ .

The stopping distance for the car traveling at 30 mph is

$d=1.1\times 30+0.055\times 30^2\\\Rightarrow d=82.5\approx 83\ \text{feet}$

The stopping distance for the auto traveling at 30 mph is $83\ \text{feet}$ .

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4 0

3 years ago

The University of Texas at Austin has three times as many students enrolledas the University of Miami. The University of Califor

harina [27]

Answer:

University of Texas has 46,500 students, University of California has 34,000 students and University of Miami has 15,500 students.

Step-by-step explanation:

Represent Texas with T, Miami with M and California with C. With the given information, the following equations were obtained.

T = 3 × M

T – 3M = 0 ………………………….(i)

C = 3,000 + 2 × M

C – 2M = 3,000…………………..(ii)

T + C + M = 96,000…………….(iii)

By rearranging, we have:

1T + 0C – 3M = 0 ………………………….(i)

0T + 1C – 2M = 3,000…………………..(ii)

1T + 1C + 1M = 96,000………….…….(iii)

The Augmented Matrix is:

$\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]$ $\left[\begin{array}{ccc}T\\C\\M\end{array}\right]$ = $\left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]$

Making $\left[\begin{array}{ccc}T\\C\\M\end{array}\right]$ the subject of the formula we have:

$\left[\begin{array}{ccc}T\\C\\M\end{array}\right]$ = $\frac{\left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]}{\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]}$

Let’s say matrix A = $\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]$ , the inverse of matrix A = $\left[\begin{array}{ccc}\frac{1}{2} &-\frac{1}{2} &\frac{1}{2} \\-\frac{1}{3} &\frac{2}{3} &\frac{1}{3} \\-\frac{1}{6} &-\frac{1}{6} &\frac{1}{6} \end{array}\right]$ is determined by the formula $\frac{Adjoint(A)}{determinant(A)}$ . This can also be computed directly on a scientific calculator.

$\left[\begin{array}{ccc}T\\C\\M\end{array}\right]$ = $\left[\begin{array}{ccc}\frac{1}{2} &-\frac{1}{2} &\frac{1}{2} \\-\frac{1}{3} &\frac{2}{3} &\frac{1}{3} \\-\frac{1}{6} &-\frac{1}{6} &\frac{1}{6} \end{array}\right]$ $\left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]$

= $\left[\begin{array}{ccc}46,500\\34,000\\15,500\end{array}\right]$