Let volleyball be v and let basketball be b.
v : b = 4 : 7, b = 21
v : 21 = 4 : 7
v/21 = 4/7
7*v = 4*21
v = 4*21/7
v = 4*3
v = 12
Volleyballs are 12
Hope this helps.
The paragraph to show the comparision between two classes semester grades on the basis of the terms
- extremes
- quartiles
- medians
- ranges
is given below:
<h3>What is Box and Whisker plots?</h3>
A box and whisker plot is defined as a graphical method of displaying variation in a set of data.
From the first figure, write all the values where dark point is drawn
53, 62, 80, 86, 89
- The lower extreme is the smallest value, which is 53.
The upper extreme is the highest value, which is 89.
- The median will be the middle of data , which is 80
- The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.
The upper quartile is 86 and the lower quartile is 62.
= Highest - Lowest
=89-53
=36
From the second figure, write all the values where dark point is drawn
56, 62, 74, 89, 96
- The lower extreme is the smallest value, which is 56.
The upper extreme is the highest value, which is 96.
- The median will be the middle of data , which is 74.
- The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.
The upper quartile is 89 and the lower quartile is 62.
= Highest - Lowest
=96-62
=34
From the above discussion,
- The First class have less upper extreme value than the second class.
- The First class have less lower extreme value than the second class.
- The First class have greater median than the second class.
- The First class have less upper quartile than the second class.
- The First and second class have equal lower quartile.
- The First class have greater range than the second class.
The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.
learn more about box and whisper plot here:
brainly.com/question/11859288
#SPJ1
3 tan³ t(theta) = tan t(theta)
3 tan³ t - tan t = 0
tan t ( 3 tan² t - 1 ) = 0
tan t = 0
t 1 = k π , k ∈ Z
3 tan ² t - 1 = 0
3 tan ² t = 1
tan ² t = 1/3
tan t = +/- √3/3
t 2 = π / 6 + k π
t 3 = - π / 6 + k π , k ∈ Z
Answer:
domain is basically x and range is y, so -2,5 -2 is domain and 5 is range
Step-by-step explanation:
Answer:
Number 4
Step-by-step explanation:
Side-Angle-Side, it has to be between the two sides.
