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spayn [35]
3 years ago
5

Which expression can be used to find 25 percent of 88?

Mathematics
2 answers:
Dominik [7]3 years ago
6 0

Answer: 25/100* 88

Step-by-step explanation:

Mariulka [41]3 years ago
6 0

Answer:

88?

Step-by-step explanation:

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Jasmine buys 3 T-Shirts and 3 Hats for $11.25. The next day, he buys 4 T-Shirts and 2 Hats for $10. How much does each T-Shirt a
leonid [27]

Answer: Each shirt costs $1.25, and each hat costs $2.5.

Step-by-step explanation:

Let x= Cost per T-shirt, y = Cost per Hat.

As per given,

3x+3y=11.25        (i)

4x+2y=10             (ii)

Multiply 4 to equation (i)

12x+12y=45          (iii)

12x+6y= 30             (iv)

Eliminate (iv) from (iii), we get

6y= 15

⇒ y = 2.5

Put value of y in (i)

3x+3(2.5)=11.25

⇒3x+7.5=11.25

⇒3x= 3.75

⇒x= 1.25

Hence, each shirt costs $1.25, and each hat costs $2.5.

8 0
3 years ago
Subtract fifteen and eighty-eight ten thousandths from twenty-six. Express your answer in numerical and word form.
Arlecino [84]

Answer:

4.9912 or four and nine thousand nine hundred twelve thousandths

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
20 POINT TO THE FIRST ANSWER + BRAINLIEST!!!
love history [14]
The cost of aquiring the source is high, i believe
3 0
3 years ago
What is the anwser -13-4x=x+7
Luden [163]

-13-4x=x+7

+13         +13

-4x=x+20

-x    -x

-5x=20

/-5   /-5

x=-4

---

hope it helps

7 0
3 years ago
The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of
Lilit [14]

Check the picture below.

\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill

\bf sin(\theta ) \implies \cfrac{\stackrel{opposite}{-1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{-1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies -\cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies -\cfrac{\sqrt{2}}{2}

\bf cos(\theta ) \implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies \cfrac{\sqrt{2}}{2} \\\\\\ tan(\theta ) = \cfrac{\stackrel{opposite}{-1}}{\stackrel{adjacent}{1}}\implies tan(\theta ) = -1

7 0
3 years ago
Read 2 more answers
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