Which expression can be used to find 25 percent of 88?
2 answers:
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Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.
In a normal distribution with mean and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sampling proportions of a proportion p in a sample of size n has mean
and standard error
In this problem:
- 1,190 adults were asked, hence
- In fact 62% of all adults favor balancing the budget over cutting taxes, hence
.
The mean and the standard error are given by:
The probability of a sample proportion of 0.59 or less is the <u>p-value of Z when X = 0.59</u>, hence:
By the Central Limit Theorem
has a p-value of 0.0166.
0.0166 = 1.66% probability of a sample proportion of 0.59 or less.
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213
Answer:
The probability that the card selected bears a number less than 34 is 0.3333.
Step-by-step explanation:
Let random variable <em>X</em> be defined as the number on the selected card.
There are <em>N</em> = 15 total cards.
The number on the cards are as follows:
S = {25, 26, 27,..., 38, 39}
The probability of an event, <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.
In this case we need to compute the probability that the card selected bears a number less than 34.
The favorable outcomes are:
<em>s</em> = {25, 36, 37, 38, 39}
<em>n</em> (X < 34) = 5
Compute the probability that the card selected bears a number less than 34 as follows:
Thus, the probability that the card selected bears a number less than 34 is 0.3333.