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dmitriy555 [2]
3 years ago
6

a) Write a program that prompts for an integer—let’s call it X—and then finds the sum of X consecutive integers starting at 1. T

hat is, if X=5, you will find the sum of 1+2+3+4+5=15.b) Modify your program by enclosing your loop in another loop so that you can find consecutive sums. For example , if 5 is entered, you will find five sum of consecutive numbers:1 = 11+2 = 31+2+3 =61+2+3+4 =101+2+3+4+5 =15Print only each sum, not the arithmetic expression.
Computers and Technology
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

<u>Solution a</u>

  1. n = int(input("Enter an integer: "))
  2. sum = 0
  3. for x in range(1, n+1):
  4.    sum += x  
  5. print(sum)

<u>Solution b</u>

  1. n = int(input("Enter an integer: "))
  2. for a in range(1, n + 1):
  3.    sum = 0
  4.    for x in range(1, a+1):
  5.        sum += x
  6.    print(sum)

Explanation:

Solution code is written in Python 3.

<u>Solution a</u>

First get the user input for an integer (Line 1).

Create a variable sum and initialize it with zero value (Line 3).

Create a for loop to traverse through the number from 1 to integer n (inclusive) and sum up the current number x (Line 5-6).

Print the sum to terminal (Line 8).

<u>Solution b</u>

Create an outer for loop that traverse through the number from 1 to integer n (inclusive) (Line 3).

Create an inner loop that traverse through the number from 1 to current a value from the outer loop and sum up the current x value (Line 5-6).

Print the sum to terminal (Line 7) and proceed to next iteration and reset the sum to zero (Line 4).

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Def sum_divisors(n): sum =1 # Return the sum of all divisors of n, not including n x=int(n**0.5) for i in range(2,(x//1)+1): if
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