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evablogger [386]
2 years ago
10

Impaired drivers are one of the many risks drivers face on the Highway Transportation System. List 3 signs that a driver could b

e potentially impaired. Explain a strategy that you can use to keep yourself safe.​
Computers and Technology
2 answers:
tekilochka [14]2 years ago
3 0
Three signs a driver could be potentially impaired is swerving on the road, driving slower than “normal” speed limit, and driving outside of the lines (when not changing lanes).

A strategy to keep yourself safe from impaired drivers could be to keep a safe distance from drivers nearby that are exhibiting erratic or potentially dangerous driving behavior.
4vir4ik [10]2 years ago
3 0

Answer:

slow driving, tailgating, and not following road lines. steer ahead or pull off the side of the road to avoid these people.

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Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
30 POINTS FOR THE CORRECT ANSWER
Nonamiya [84]

In the case above, Ruben  should consider the printing option below:

  • Offset litho printing.
  • Digital Printing.
  • Screen printing.

<h3>What is the best printing type for books?</h3>

The use of digital printing is known to be the best in the case with Ruben. It is said to be much more economical in terms of shorter print runs.

Note that Digital printing do have fast turnaround time and as such it is better for books.

Therefore, In the case above, Ruben  should consider the printing option below:

  • Offset litho printing.
  • Digital Printing.
  • Screen printing.

Learn more about printing from

brainly.com/question/145385

#SPJ1

5 0
1 year ago
Hoda wants to create a new presentation in PowerPoint with existing graphics and designs. What is the easiest and fastest way fo
Paul [167]

Answer: a

Explanation:

6 0
3 years ago
UML is a graphical language that is used for designing and documenting software created within the _____________ framework. (a)
stealth61 [152]

Answer:

The answer is "option d".

Explanation:

UML stands for Unified Modeling Language. It is an OOPs based language that is used to design a graphic by software developers. This language can also be used to build diagrams and provide some tools to ready-to-use, interactive templates for users and other options are not correct that can be described as:

  • In option a, The Top-down approach is not followed by UML.
  • In option b, UML uses an object-oriented programming language that follows a bottom-up approach. It refers to a style of programming.
  • In option c, It does not use structured programming because it uses procedural languages.

7 0
2 years ago
Shelly and Donna are discussing System Restore. Shelly says when the System Restore program creates and saves a copy of your com
pav-90 [236]
The answer is D, because it's called a back-up.
4 0
3 years ago
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