Answer:
Function sparse code is
def sparse(a):
rl = []
cl = []
for i in range(0,len(a)):
rl.append(a[i][1])
cl.append(a[i][2])
r = max(rl)
c = max(cl)
s = []
k = 0
for i in range(0,r+1):
s.append([])
for j in range(0,c+1):
if (i==a[k][1]) & (j == a[k][2]):
s[i].append(a[k][0])
k = k+1
else:
s[i].append(0)
return s
def main():
k = sparse([[3,1,2],[4,5,3]])
print(k)
if __name__ == '__main__':
main()
Explanation:
Please see attachment for output
Answer:
The given problem is solved using language - Python.
def f(x):
new_list=[]
for i in x:
if i%2==0:
new_list.append(i//2)
else:
new_list.append(i*2)
return new_list
my_list=list(range(1,6))
print('Original List:',my_list)
my_list=f(my_list)
print('Modified List:',my_list)
There is another way of doing this - By using map() function.
—————————————————————————————
def f(x):
return list(map(lambda x:x//2 if x%2==0 else 2*x,x))
my_list=list(range(1,6))
print('Original List:',my_list)
my_list=f(2my_list)
print('Modified List:',my_list)
—————————————————————————————
Original List: [1, 2, 3, 4, 5]
Modified List: [2, 1, 6, 2, 10]