Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
Equation: 500 = 50 + 15x
Step-by-step explanation:
where x is the number of weeks Nick will have to deposit $15 in order to accumulate $500, given that the first week he deposited $50.
500 = 50 + 15x
500 = 50 + 15x
450 = 15x
x = 30
Now Nick will have to deposit $15 each week for 30 weeks. This is in addition to the $50 deposit he made week 1. So it will take him 31 total deposits to accumulate the $500.
Well, if y is the notebook cost, well x+y=6.28, x+x+0.70=6.28, 2x=5.58, x=2.79.
The pencil box costs $2.79, while the notebook costs $3.49.
The axis of symmetry is 2 and the vertex is (2, 4).
