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Use the limits to find the area between the curve and the X-axis for the given interval y = x ^ 3 from x = 0 to x = 1

viva [34]

Answer:

1/4

Step-by-step explanation:

D

6 0

3 years ago

The researcher trains a sample of 16 individuals in mindfulness and then collects data on how long they spend eating per day. Th

Mila [183]

Answer:

The calculated t-value is t=0.47.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Americans typically eat quickly and do not spend time enjoying their meal. A researcher plans to test if those trained in mindfulness will take more time to enjoy their meal (that is, they will spend more time eating than the general population). The general population spends an average of 68 minutes per day combined eating their three meals. The researcher trains a sample of 16 individuals in mindfulness and then collects data on how long they spend eating per day. The sample mean for those trained in mindfulness equals 74; the SS = 150. What is the calculated t-value? Round your answer to two decimal places."</em>

The degrees of freedom are (n-1)=(16-1)=15

The standard deviation is:

$s=\sqrt{\frac{SS}{n-1}}=\sqrt{\frac{150}{16-1}}=\sqrt{10}=3.16$

The t-value can be calculated as:

$t=\frac{M-\mu}{\sigma/\sqrt{n}} =\frac{74-68}{3.16/\sqrt{16}} \\\\t=\frac{6}{3.16*4}=\frac{6}{12.64}= 0.47$

4 0

3 years ago

How do write fifty and six hundredths in standard form

BaLLatris [955]

Well before the descimal its 5,600 after decimal is 0.56

5 0

3 years ago

News article reports that "Americans have differing views on two potentially inconvenient and invasive practices that airports c

OverLord2011 [107]

Answer:

1) p1=0.83

2) p2=0.81

3) Option B

4) p=0.82

5) s=0.03

6) z=0.67

7) P=0.50

8) Do not reject H0

Step-by-step explanation:

1) The proportion of Republicans who think the full-body scans should be applied in airports is equal to the ratio between the republicans that think it should over the total Republicans in the poll:

$p=X/n=258/311=0.83$

2) The proportion of Democrats who think the full-body scans should be applied in airports is equal to:

$p=X/n=294/363=0.81$

3) As we want to know if there is a difference in the proportions calculated, not if one is higher or lower than the other, the correct option is B:

$H_0:p_1-p_2=0\\\\H_a:p_1-p_2\neq0$

4) The pooled estimate of a proportion is the average of both proportions:

$\bar{p}=\frac{p_1+p_2}{2}= \frac{0.83+0.81}{2}=0.82$

5) The standard error can be calculated as:

$s=\sqrt{\frac{\bar{p}(1-\bar{p})}{n_1} +\frac{\bar{p}(1-\bar{p})}{n_2}} \\\\s=\sqrt{\frac{0.82*0.18}{311} +\frac{0.82*0.18}{363}} \\\\s=\sqrt{0.00047+0.00041} =\sqrt{0.00088}=0.03$

6) The z-statistic can be calculated as:

$z=\frac{p_1-p_2}{s}=\frac{0.83-0.81}{0.03}=\frac{0.02}{0.03}=0.67$

7) The P-value for z=0.67 is P=0.50 (from the standard normal distribution table).

$2P(Z>|z|)=0.50286$

8) If the significance level is 0.01, the P-value is bigger than the significance level. The effect is not significanct. The null hypothesis is not rejected.

There is not enough evidence to say that both proportions are different.

A. Do not reject H0

8 0

3 years ago

According to a recent survey, the population distribution of number of years of education for self-employed individuals in a c

creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean $\mu$ and standard deviation $\sigma$ , then the distribution of sample mean will be normally distributed with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

b) mean and the standard for a random sample of size 49

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4$

c) mean and the standard for a random sample of size 196

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2$

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0

3 years ago