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Pepsi [2]
4 years ago
12

The smallest volume from among the following is

Chemistry
1 answer:
Nataly_w [17]4 years ago
3 0
The smallest volume from among the following is <span>0.012L.</span>
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The expression 2Ag + SAg2S is called a(n)
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I guess it is called an Equation !!
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When can the park be reopen to people and animals. Explain calculations and answers. Explain the concept.
julsineya [31]

Answer:

in 23 years

Explanation:

5 0
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How many Calories are there in 4600 Joules?
mars1129 [50]

Answer:

1099.426

Explanation:

4 0
4 years ago
onsider the reaction, NO2(g) + CO(g) → NO(g) + CO2(g), for which the rate law has been determined to be: Rate = k[NO2]2[CO]. Whi
nlexa [21]

Answer:

The correct answer is option D.

Explanation:

Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.

NO_2(g) + CO(g)\rightarrow NO(g) + CO_2(g)

Rate of the reaction:

R=-\frac{1}{1}\times \frac{d[NO_2]}{dt}=-\frac{1}{1}\times \frac{d[CO]}{dt}

Rate of decrease in nitrogen dioxide concentration is equal to the rate of decrease in carbon monoxide.

Given rate expression of the reaction:

R = k[NO2]^2[CO]

Rate of the reaction on doubling concentration of nitrogen dioxide and carbon monoxide : R'

R'=k(2\times [NO_2])^2(2\times [CO])=8\times k[NO2]^2[CO]=8R

Doubling the concentrations of nitrogen dioxide and carbon monoxide simultaneously will increase the rate of the reaction by a factor of eight.

Hence, none of the given statements are true.

6 0
3 years ago
Read 2 more answers
The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this
nevsk [136]

Answer:

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }

The given reaction involves the decomposition of H2O into H2 and O2

2H_{2}O\rightleftharpoons 2H_{2} + O_{2}

The equilibrium constant is expressed as :

Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Since Keq = 5.31*10^-10

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

3 0
3 years ago
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