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ioda
3 years ago
6

Wine goes bad soon after opening because the ethanol in it reacts with oxygen gas from the air to form water and acetic acid , t

he main ingredient of vinegar. What mass of ethanol is consumed by the reaction of 3.37g oxygen gas?
Chemistry
1 answer:
ryzh [129]3 years ago
5 0

The mass of ethanol is consumed by the reaction of 3.37g oxygen gas is 4.85g

Explanation:

The balanced equation for the chemical reactions is;

CH₃CH₂OH + O₂ → CH₃COOH + H₂O

The mole ratio between oxygen and ethanol in the reaction is 1 : 1

The molar mass of O₂ is 32g / mole. Therefore the O₂ moles consumes in the reaction is;

3.37 / 32

If the molar mass of ethanol is 46.07g/mole, and the ration of reaction in 1 : 1; Then the moles of ethanol consumed is;

3.37/32 * 46.07

= 4.85g

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Answer:

The answer to your question is None, sulfur share of its electrons

Explanation:

Just remember:

Sulfur, S, has 6 electrons in its outermost shell

Hydrogen, H, has 1 electron in its outermost shell

Oxygen, O, has 6 electrons in its outermost shell

See the picture below

The electrons of sulfur are in blue

The electrons of oxygen are in red

The electron in hydrogen is in yellow

Sulfur is the central atom and it shares all its electrons with the oxygen.

                     

8 0
4 years ago
A malfunction at a power station causes a power surge in certain homes near the station. Some televisions and computers begin ma
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Answer:A surege protector

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4 0
3 years ago
What is the molarity of a solution that contains 224 grams of KOH in 2<br> liters of solution?
adelina 88 [10]

Answer:

\boxed {\boxed {\sf 2 \ M \ KOH}}

Explanation:

Molarity is a measure of concentration in moles per liter.

<h3>1. Grams to Moles </h3>

The first step is to convert the amount of grams given to moles. The molar mass is used. This found on the Periodic Table and it's the same value as the atomic mass, but the units are grams per mole.

We have 224 grams of KOH. Look up the molar masses for the individual elements.

  • Potassium (K): 39.098 g/mol
  • Oxygen (O): 15.999 g/mol
  • Hydrogen (H): 1.008 g/mol

Since the compound's formula has no subscripts, 1 formula unit has 1 atom of each element. We can simply add the molar masses together to find KOH's molar mass.

  • KOH: 39.098 + 15.999 + 1.008=56.105 g/mol

Use this number as a ratio.

\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}

Multiply by the value we are converting: 224 g KOH

224 \ g \ KOH *\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}

Flip the ratio so the units of grams KOH cancel.

224 \ g \ KOH *\frac {1 \ mol \ KOH}{56.105 \ g\ KOH}

224 *\frac {1 \ mol \ KOH}{56.105}

\frac {224}{56.105} \ mol \ KOH

3.992514036 \ mol \ KOH

<h3>2. Calculate Molarity </h3>

Remember molarity is moles per liter.

molarity = \frac{moles}{liters}

We just calculated the moles and we know there are 2 liters of solution.

molarity = \frac{ 3.992514036 \ mol \ KOH}{ 2 \ L}

molarity= 1.996257018 \ mol \ KOH/ L

<h3>3. Round and Convert Units </h3>

First, let's round. The original values have 3 and 1 significant figures. We go with the lowest number: 1. For the number we found, that is the ones place.

  • 1.<u>9</u>96257018

The 9 in the tenths place tells us to round to 1 up to a 2

2 \ mol \ KOH/ L

Next, convert units. 1 mole per liter is equal to 1 molar or M.

2 \ M \ KOH

The molarity of the solution is <u>2  M  KOH</u>

6 0
3 years ago
Read 2 more answers
1. When 50.0 mL of water at 80.0°C was mixed with 50.0 mL of water in a calorimeter at
ddd [48]

Answer:

The heat capacity of the calorimeter is 5.11 J/g°C

Explanation:

Step 1: Given data

50.0 mL of water with temperature of 80.0 °C

Specific heat capacity of water = 4.184 J/g°C

Consider the density of water = 1g/mL

50.0 mL of water in a calorimeter at 20.0 °C

Final temperature = 47.0 °C

Step 2: Calculate specific heat capacity of the water in calorimeter

Q = Q(cal) + Q(water)

Q(cal) = mass * C(cal) * ΔT

Qwater = mass * Cwater * ΔT

Qcal = -Qwater

mass(cal) * C(cal) * ΔT(cal) =  mass(water) * C(water) * ΔT(water)

50 grams * C(cal) * (47.0 - 20.0) =- 50grams * 4.184 J/g°C * (47-80)

1350 * C(cal) = 6903.6

C(cal) = 5.11 J/g°C

The heat capacity of the calorimeter is 5.11 J/g°C

8 0
3 years ago
What if the volume of the cylinder?
Rzqust [24]

Answer:

653.45

Explanation:

pi * 4 by the power of 2 * 13 ~653.45

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