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lina2011 [118]
3 years ago
12

A water park charges $5 for entry into the park and an additional $2 for each of the big water slides. Steven spent $17 on his v

isit to the water park. Which equation can be used to find the number of big water slides, x, that Steven went on?
Mathematics
2 answers:
morpeh [17]3 years ago
7 0
LET X= ADDITIONAL AMOUNT
<u>EQAUTION=</u> 5+2x=17
                      -5       -5
                    __________
                      2x=12
                     _______
                      2     2
                       X=6 IS THE ANSWER. HOPE THIS HELPS!!!!!
Gelneren [198K]3 years ago
3 0
5+2x=17 is the equation, since he spends five dollars initially, 17 total, and spends two more for every "big water slide".
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B. Yes, because P(X ≥ 68) ≤ .05

Step-by-step explanation:

The probability of a score X occuring is said to be unusually high if the probability of a score of X or larger is lower than 5%.

For each student, there are only two possible outcomes. Either they think that the court shows too much concern for criminals, or they do not think this. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Three out of four students said that courts show too much concern for criminals. This means that p = \frac{3}{4} = 0.75

Would 68 be considered an unusually high number of students who feel that courts are partial to criminals?

We have to find P(X \geq 68).

P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 68) = C_{70,68}.(0.75)^{68}.(0.25)^{2} < 0.000001

P(X = 69) = C_{70,69}.(0.75)^{69}.(0.25)^{1} < 0.000001

P(X = 70) = C_{70,70}.(0.75)^{70}.(0.25)^{0} < 0.000001

So

P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70) < 0.000003

P(X \geq 68) is lower than 0.05, so this is an unusually high number.

So the correct answer is:

B. Yes, because P(X ≥ 68) ≤ .05

5 0
3 years ago
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