No,
one of the 3 sides need to be 90
<h3>Answer to Question 1:</h3>
AB= 24cm
BC = 7cm
<B = 90°
AC = ?
<h3>Using Pythagoras theorem :-</h3>
AC^2 = AB^2 + BC ^ 2
AC^2 = 24^2 + 7^2
AC^2 = 576 + 49
AC^2 = √625
AC = 25
<h3>Answer to Question 2 :-</h3>
sin A = 3/4
CosA = ?
TanA = ?
<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>
(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)
<h3>Using Pythagoras theorem :-</h3>
AC^2 = AB^2 + BC ^ 2
4² = AB² + 3²
16 = AB + 9
AB = √7cm
<h3>CosA = Adjacent side/Hypotenuse</h3>
= AB/AC
= √7/4
<h3>TanA= Opp. side/Adjacent side</h3>
=BC/AB
= 3/√7
Answer:
1. 10x^2 -4
2. 2a^5 + 5b
Step-by-step explanation:
1. Simplify 4(x^2 -1) to 4x^2 -4
then add that to 6x^2
2. 4a^5 - 2a^5 = 2a^5 and
4b+b = 5b
Answer:
73
Step-by-step explanation:
Angle JID is supplementary to Angle JIH so:
180- Angle JIH= Angle JID
180-107=73
Angle JID is opposite to Angle AJF(angle x)
Opposite angles are always equal
Angle JID=Angle AJF(x)
73=Angle AJF(x)
Vera has 5 pairs of necklaces and wants to own 22 pairs. That means she needs to purchase 17 pairs at $1 per pair.
Vera needs to spend $17.
