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dusya [7]
2 years ago
13

Question 10 of 25

Mathematics
1 answer:
nataly862011 [7]2 years ago
6 0

Answer: Your answer should be A

Step-by-step explanation: The line with a open hole will not have an equal sign where a closed hole will.

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How to multiply 11*121
soldier1979 [14.2K]

Answer:1,331

Step-by-step explanation:put 121 on top and 11 on the bottom then start multiply , or you could use a calculator / Photo-math if you’re feeling lazy

5 0
3 years ago
A home is to be built on a 56 foot 9 inch wide lot. The house is 5 feet 5 inches from the side of the lot and is 34 feet 10 inch
daser333 [38]
<span>Total lot - house -other side
=(56 ft 9 in) - (34 ft 10 in) - (5 ft 5 in)
=(55 ft 21 in) - (34 ft 10 in) - (5 ft 5 in)
=16 ft 6 in
Convert to inches: </span>16 ft x 12 in/ft)+ 6 in= Total in inches<span>192 in + 6 in= Total in inches
198 in= Total in inches 
Check: One side + house + other side = Lot width
(5 ft 5 in)+(34 ft 10 in)+(16 ft 6 in)=Lot width
56 ft 9 in=Lot width, which equals the given.</span>
8 0
3 years ago
Write down all the prime numbers between 15 and 25
Tju [1.3M]
17,19,23 are the prime numbers
8 0
3 years ago
Read 2 more answers
How do i turn -187/2 into a decimal? :) thxs for helping if u do btw
steposvetlana [31]

Answer:

-93.5

Step-by-step explanation:

Divide -187 by 2

6 0
3 years ago
Solve the following system by any method -8x-8y=0 -8x+2y=-20
iVinArrow [24]
                     \fbox{Solution by using Matrix} 

\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20

\text{Rewrite the linear equations above as a matrix} 

\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right] 

\text{Apply to Row2 : Row2 + Row1} 

\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right] 

\text{ Simplify rows} 

\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right] 

\text{Note: The matrix is now in echelon form.}\text{The steps below are for back substitution.} 

\text{Apply to Row1 : Row1 + 8 Row2} 

\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right] 

\text{ Simplify rows}  

\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right] 

\text{Therefore, the solution is} 

x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}
7 0
3 years ago
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