3,471 into scientific notation

You are running a fuel economy study. One of the cars you find is blue. It can travel 43 1/2 miles on 1 1/4 gallons of gasoline

nignag [31]

Answer:

Blue

Step-by-step explanation:

Blue = 43.5/1.25

34.8 mpg

Red = 21 3/5 / 4/5 = 21.6/0.8

27 mpg

4 0

2 years ago

Candy takes 57 minutes to deliver all the paper whereas Tim takes 114 minutes. How long does it take them where they work togeth

kow [346]

-- Candy takes 57 minutes to do the whole job ==>
She does 1/57 of the job every minute.

-- Tim takes 114 minute to do the whole job ==>
He does 1/114 of the job every minute.

-- If they work together, they do (1/57 + 1/114) of the job every minute.
We have to add those fractions.

The least common denominator is 114.

   (1/57 + 1/114)

   = (2/114 + 1/114)

   =    3/114 = 1/38 .

Working together, Candy and Tim do 1/38 of the job every minute.

So it takes them 38 minutes to do the whole job together.

4 0

3 years ago

When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis

Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so $\mu = 22, \sigma = 4$ .

What is the probability that a fisherman catches a spotted seatrout within the legal limits?

They must be between 10 and 30 inches.

So, this is the pvalue of the Z score of $X = 30$ subtracted by the pvalue of the Z score of $X = 10$

X = 30

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{30 - 22}{4}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

X = 10

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 22}{4}$

$Z = -3$

$Z = -3$ has a pvalue of 0.00135.

This means that there is a 0.9772-0.00135 = 0.97585 = 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

3 0

2 years ago

I need help with this please

olganol [36]

The correct answer would be J

8 0

2 years ago

Someone please solve and explain part a(i)

Crank

Step-by-step explanation:

the way I understand the description :

C is below B. they are on a kind of straight hill, and there is a straight "road" going up from C to B.

then, at B there is an antenna or other firm of mast going straight up.

therefore, this is not a right-angled triangle with 90 degrees at B (as it would be, if this would be in a flat plane).

but because it goes downhill from B to C the angle is 105 degree.

(a)(i)

now, imagine, there would be a horizontal plane either at B or at C. AB would have a true 90 degree angle with this plane. so, what is the angle of CB with this plane ?

this angle is the "excess" of the 90 degrees, as CB angles down from the horizontal plane at B, or angles up with the same angle from the horizontal plane at C.

what is the "excess" of 105 degrees vs. the standard 90 degrees ? 105 - 90 = 15 degrees.

(a)(ii)

the extended Pythagoras for not right-angled triangles :

c² = a² + b² - 2ab×cos(B)

B being the angle opposite of the Hypotenuse c.

so, we have

c² = 15² + 10² -2×15×10×cos(105) = 225 + 100 - 300×cos(105) =

= 325 - 300×cos(105) = 402.6457135...

c = 20.06603383... ≈ 20 m

4 0

2 years ago