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3 years ago

Jessica made 2 pounds of fudge. How many -pound servings are in the 2 pounds of fudge?

Mathematics

1 answer:

Elina [12.6K]3 years ago

7 0

Answer:

Step-by-step explanation:

2 pounds of fudge ÷ 1 pounds servings = 2 servings

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Julio scores 18 points in each basketball game. If there are 14 games in a season and Julio continues to score 18 points each ga

igor_vitrenko [27]

First, multiply the # of points he scores a game by the # of games in the season:

18x14= 252points

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4 years ago

^ need help !!!!!!!!!!!!!!!!!!!!

elena-14-01-66 [18.8K]

First set up the equation to find answer: y=7-x. Then add it to the variable. 3x-1(7-x)=1. So that makes it 3x+-7+-1=1. Add like terms -7+-1=-8, so 3x+-8=1. Now to find x just switch the 8 to the other side. So you end up with 3x=9 since when you take away a number from one side you need to use the opposite value so adding 8 to -8 will cancel it out, then add it to the other, then just divide. 9/3=3, from here just substitute to find y. y=7+3. y=10. The answer is x=2 and y=5. I hope I helped!

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3 years ago

Read 2 more answers

P is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin O to P, is a minimum. Find the

nirvana33 [79]

The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: d2=(x−0)^2+(y−0)^2
 =x^2+y^2

To minimize this function d^2 subject to the constraint, 2x+y−10=0
If we substitute, the y-values the distance function can take will be related to the x-values by the line:y=10−2x
You can substitute this in for y in the distance function and take the derivative:
d=sqrt [x2+(10−2x)^2]

d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)
Setting the derivative to zero to find optimal x,
d′=0→10x−40=0→x=4

This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).

Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).

8 0

4 years ago

You decided to put the 94 lollipops on sale.if you charge 70cents and put them on sale for buy one,get one free,will you be char

Svet_ta [14]

$0.70 for 2 lollipops
X for 94 lollipops
So, 2X=94*0.70
X= (94*0.70)/2 = 65.8/2
X= $32.9
The answer is YES. They are charging enough money to get $32.90 after selling 94 lollipops on sale for buy one and get one for free.

8 0

3 years ago

What is number 61 and a step by step explaination please?

astra-53 [7]

1/3 ln(x) + ln(2) - ln(3) = 3

Recall that $m\log_b(n)=\log_b(n^m)$ , so

ln(x ¹ʹ³) + ln(2) - ln(3) = 3

Condense the left side by using sum and difference properties of logarithms:

$\log_b(m)+\log_b(n)=\log_b(mn)$

$\log_b(m)-\log_b(n)=\log_b\left(\dfrac mn\right)$

Then

ln(2/3 x ¹ʹ³) = 3

Take the exponential of both sides; that is, write both sides as powers of the constant e. (I'm using exp(x) = e ˣ so I can write it all in one line.)

exp(ln(2/3 x ¹ʹ³)) = exp(3)

Now exp(ln(x)) = x for all x, so this simplifies to

2/3 x ¹ʹ³ = exp(3)

Now solve for x. Multiply both sides by 3/2 :

3/2 × 2/3 x ¹ʹ³ = 3/2 exp(3)

x ¹ʹ³ = 3/2 exp(3)

Raise both sides to the power of 3:

(x ¹ʹ³)³ = (3/2 exp(3))³

x = 3³/2³ exp(3×3)

x = 27/8 exp(9)

which is the same as

x = 27/8 e ⁹

3 0

3 years ago