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Nezavi [6.7K]
4 years ago
13

Your network employs basic authentication that centers on usernames and passwords. However, you have two ongoing problems. The f

irst is that usernames and passwords are frequently lost by negligent users. In addition, adversaries have, on occasion, fooled employees into giving up their authentication information via social engineering attacks. Discuss at least two things could you do to strengthen the use of basic username and password authentication, as discussed in the course textbook.
Computers and Technology
1 answer:
Agata [3.3K]4 years ago
8 0

Answer:

Using a one time password OTP and using a three factor authentication.

Explanation:

Social engineering is a form system and network attack, drafted by an attacker, to steal user credentials needed for accessing their accounts, to steal information.

Social engineering attacks like phishing, spear phishing, baiting and quid quo pro are used to fool users to giving out their user details.

One time password is an implied use of a password just once and a new password his generated to boost security. In a three factor authentication, OTP can be used as well as biometrics of a user which can not be giving away by a user to an attacker.

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You are hired by a game design company and one of their most popular games is The Journey. The game has a ton of quests, and for
Kamila [148]

Answer:

Explanation:

Let's describe the connected part for the very first time.

Component with good connections:-

A semi in any graph 'G' is defined by a way to align element if this can be crossed from the beginning of any link in that pixel or if this can be stated that there is a path across each organized node pair within this subgram.

Consecrated pair means (ni, nj) and (nj, ni) that 2 different pairs would be regarded.

In point a:

We're going to be using contradictions for this segment. They start with the assumption that two lucky journeys are not even in the same strongly interconnected component.

For instance, qi and qj are providing special quests that were not in the very strongly linked element and which implies that, if we start to cross from qi or qi, then qj cannot be approached if we begin to move through qj and as we established if qi or qj is fortunate contests, we may reach any other hunts. Which implies qj from qi or conversely should be reachable. Or we might claim that qi is part of the strongly linked portion of qj or vice versa with this situation.

Consequently, we would not be capable of forming part of a different and strongly linked element for two successful scientists; they must have the same strongly related to the element.

In point b:

Its definition of its strong, line segment indicates that all other searches within such a strongly coordinate system can be made possible from any quest. Because if all quests are accessible from any quest then a lucky search is named, and all other quests can be accessed from any quest in a very coordinated system. So, all contests are fortunate contests in a strongly connected element.

Algorithm:

Build 'n' size range named 'visited' wherein 'n' is the number of graphic nodes that keep records of nodes already frequented.  Running DFS out of every unknown vertex or mark all edges as seen.  The lucky search will be the last unexplored peak.

Psuedo-Code:

Requires this functionality to also be called Solution, it requires 2 reasons as an input, V is a set of objects in graph 'G' and 'G' is a chart itself.

Solution(V, G):

visited[V] = {false}//assign value

for v: 0 to 'V'-1:  //using for loop

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DFS(v, visited, V, G)  //use DFS method

ans = v //holding value

return ans //return value

3 0
3 years ago
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What is meant by reflection?​
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6 0
3 years ago
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What do you call the parts of the motor that do not move?.
olasank [31]

Answer:

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Explanation:

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3 years ago
Polygon transform (25 points). Write a library of static methods that performs various geometric transforms on polygons. Mathema
kari74 [83]

Answer:

import java.lang.*;               //for using Math.cos() and Math.sin() and Math.toRadians() funcitons in rotate method

public class PolygonTransform

{

  public static double[] copy(double[] array)

  {

      double[] newArray = new double[array.length];

      for(int i=0;i<array.length;i++)

      {

          newArray[i] = array[i];

          return newArray;

      }

  }

  public static void scale(double[]x,double[]y,double alpha)

  {

      for(int i=0;i<x.length;i++)

      {

          x[i] *= alpha;

          y[i] *= alpha;

      }

  }

  public static void translate(double[]x,double[]y,double dx,double dy)

  {

      for(int i=0;i<x.length;i++)

      {

          x[i] += dx;

          y[i] += dy;

      }

  }

  public static void rotate(double[] x, double[]y,double theta)

  {

      double rad = Math.toRadians(theta);

      double temp;

      for(int i=0;i<x.length;i++)

      {

          temp = x[i];                           //For storing temporarily the previous value of x before changing so tha it can be used in changing y

          x[i] = x[i]*Math.cos(rad) - y[i]*Math.sin(rad);

          y[i] = y[i]*Math.cos(rad) + temp*Math.sin(rad);  

      }

  }

  public static void main(String args[])

  {

      //This is just implementing you testcase discripted.

      double[]x = new double[4];

      double[]y = new double[4];

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double alpha = 2.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      scale(x, y, alpha);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

      // Translates polygon by (2, 1).

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double dx = 2.0, dy = 1.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      translate(x, y, dx, dy);

      StdDraw.setPenColor(StdDraw.BLUE);

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      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double theta = 45.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      rotate(x, y, theta);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

  }

}

Explanation:

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1 _ A Unit of information containing the object's position: rotation, and scale values is called:
Damm [24]

Answer:

an inform

Explanation:

A information is an inform

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