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antiseptic1488 [7]
3 years ago
10

The bull’s-eye on a target has diameter 2 in. What is the area of the bull’s-eye to the nearest tenth? Use 3.14 for π

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0

Answer:

20.3cm^2

Step-by-step explanation:

Bullseye has a circular shape. So area of a bulleyse = Pi x (radius) ^2

Díameter is 2 inches = 5. 08cm

But radius = diameter /2

Radius = 5.08cm /2

Radius = 2.54cm

Hence Area of bulleyse = 3.14 x (2.54) ^2

= 3.14 x 6. 451 cm^2

= 20.256 cm^2

=20.3cm^2 (to nearest tenth)

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Answer:

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Step-by-step explanation:

Hi there!

First, let´s write the equation:

log[(x² + 2x -3)⁴] = 0

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4 log[(x² + 2x -3)⁴] = 0

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if log(x² + 2x -3) = 0, then  x² + 2x -3 = 1 because only log 1 = 0

x² + 2x -3 = 1

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x = [-b± √(b² - 4ac)]/2a

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The solutions are x = 1.24 and x = -3.24

Have a nice day!

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