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3 years ago

The bull’s-eye on a target has diameter 2 in. What is the area of the bull’s-eye to the nearest tenth? Use 3.14 for π

Mathematics

1 answer:

777dan777 [17]3 years ago

3 0

Answer:

20.3cm^2

Step-by-step explanation:

Bullseye has a circular shape. So area of a bulleyse = Pi x (radius) ^2

Díameter is 2 inches = 5. 08cm

But radius = diameter /2

Radius = 5.08cm /2

Radius = 2.54cm

Hence Area of bulleyse = 3.14 x (2.54) ^2

= 3.14 x 6. 451 cm^2

= 20.256 cm^2

=20.3cm^2 (to nearest tenth)

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Degger [83]

Answer:

Ac=60°

AB=90°

Step-by-step explanation:

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2 years ago

A coin bank that excepts only nickels and dimes contains $9.15. There are three more than twice as many nickels as there are dim

valentinak56 [21]

45 dimes and 93 nickels were in bank

<em><u>Solution:</u></em>

Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

$n \times 0.05 + d \times 0.10 = 9.15$

0.05n + 0.10d = 9.15 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

0.05(3 + 2d) + 0.10d = 9.15

0.15 + 0.1d + 0.10d = 9.15

0.2d = 9

From eqn 1

n = 3 + 2(45)

n = 3 + 90 = 93

Thus 45 dimes and 93 nickels were in bank

3 0

3 years ago

D = 8 cm<br> h = 18 cm<br> What is the surface area of the cylinder

mars1129 [50]

Answer:

144 (If multiplying)

Step-by-step explanation:

18x8=144.

5 0

3 years ago

Scenario: The Cannon Instructions: View the video found on page 1 of this Journal activity. Using the information provided in th

Artyom0805 [142]

Answer:

Part A

Yes

Part B

He will land at a point 30 meters from Cannon

Step-by-step explanation:

Part A

The given function that represent the path of the Cannon, which is the path of a parabolic arc, is presented as follows;

f(x) = -0.05·(x² - 26·x - 120)

We note that the height, 'h', of the path of a parabola at a horizontal distance, 'x' from the origin is equal to f(x)

Therefore, given that at the ground level, at the start and end of the flight, the f(x) = 0, we can write;

-0.05·(x² - 26·x - 120) = 0

∴ x² - 26·x - 120 = 0

x = (26 ± √((-26)² - 4 × 1 × (-120)))/(2 × 1)

Which gives;

x = 30 or x = -4

Therefore, he lands at a point 30 meters from the starting point

Therefore, the function gives enough information to tell where he will land

Part B

He lands at the point, x = 30 from the point the cannon was fired.

3 0

2 years ago

Question 2 Determine if (x-3) is a factor to the polynomial P(x) = 2x³ +5x²-28x - 15. (3 marks)

tangare [24]

Answer:

(x - 3) is a factor of P(x)

Step-by-step explanation:

if (x - 3) is a factor of P(x) then P(3) = 0

P(3) = 2(3)³ + 5(3)² - 28(3) - 15

= 2(27) + 5(9) - 84 - 15

= 54 + 45 - 99

= 99 - 99

= 0

since P(3) = 0 then (x - 3) is a factor of P(x)

3 0

2 years ago