What equation in slope-intercept form represents the line that passes through the points
1 answer:
<h2>Answer: y = - x + 1
</h2>
<h3>Step-by-step explanation: </h3>
For us to write the equation for this line, we need to (1) find the slope of the line, and (2) use one of the points to write an equation:
The question gives us two points, (-3, 4) and (2, -1), from which we can find the slope and later the equation of the line.
<u>Finding the Slope</u>
The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)
= (4 - (- 1)) ÷ ((-3) - 2)
= - 1
<u>Finding the Equation</u>
We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:
⇒ y - (-1) = - 1 (x - 2)
y + 1 = - (x - 2)
we could also transform this into the slope-intercept form ( y = mx + c) by making y the subject of the equation:
since y + 1 = - (x - 2)
∴ y = - x + 1
<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>
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6) check picture
a) all three lines are parellel and have the same slope. the only difference is that they are translated on different points on the x-axis.
not sure about the rest sorry :(
Check the picture below
now, we know is a parallelogram, so the diagonals will bisect
looking at the picture, the interior angles are not right-angles, and thus is not a rectangle, and is not a square either, due to the same reason
is it a rhombus? well, a rhombus, is a parallelogram, that's "slanted" per se, but regardless of how slanted it may be, the sides are all equal
now, we don't need to check the length of both pairs, just one of the segments of each pair, let's check only then JK and KL, the ones in red in the picture, since each pair of segments are twin, if JK = KL, then that means all sides are equal
![\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) J&({{-7 }}\quad ,&{{ -2}})\quad % (c,d) K&({{ 0}}\quad ,&{{ 4}})\\\\ K&({{ 0}}\quad ,&{{ 4}})\quad % (c,d) L&({{ 9}}\quad ,&{{ 2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ JK=\sqrt{[0-(-7)]^2+[4-(-2)]^2}\implies JK=\sqrt{(0+7)^2+(4+2)^2} \\\\\\ JK=\sqrt{7^2+6^2} \\\\\\ KL=\sqrt{(9-0)^2+(2-4)^2}\implies KL=\sqrt{9^2+(-2)^2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0AJ%26%28%7B%7B-7%20%7D%7D%5Cquad%20%2C%26%7B%7B%20-2%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AK%26%28%7B%7B%200%7D%7D%5Cquad%20%2C%26%7B%7B%204%7D%7D%29%5C%5C%5C%5C%0AK%26%28%7B%7B%200%7D%7D%5Cquad%20%2C%26%7B%7B%204%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AL%26%28%7B%7B%209%7D%7D%5Cquad%20%2C%26%7B%7B%202%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AJK%3D%5Csqrt%7B%5B0-%28-7%29%5D%5E2%2B%5B4-%28-2%29%5D%5E2%7D%5Cimplies%20JK%3D%5Csqrt%7B%280%2B7%29%5E2%2B%284%2B2%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AJK%3D%5Csqrt%7B7%5E2%2B6%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AKL%3D%5Csqrt%7B%289-0%29%5E2%2B%282-4%29%5E2%7D%5Cimplies%20KL%3D%5Csqrt%7B9%5E2%2B%28-2%29%5E2%7D)
now... another characteristic of a rhombus is, the diagonals, meet at right-angle, that means KM ⟂ JL
and that simply means, if you get the slope of KM and the slope of JL, the product of their slope is -1
then multiply both slopes, if their product is -1, that means, they're perpendicular to each other, and it IS a rhombus only, then.
now, we know is a parallelogram, so the diagonals will bisect
looking at the picture, the interior angles are not right-angles, and thus is not a rectangle, and is not a square either, due to the same reason
is it a rhombus? well, a rhombus, is a parallelogram, that's "slanted" per se, but regardless of how slanted it may be, the sides are all equal
now, we don't need to check the length of both pairs, just one of the segments of each pair, let's check only then JK and KL, the ones in red in the picture, since each pair of segments are twin, if JK = KL, then that means all sides are equal
now... another characteristic of a rhombus is, the diagonals, meet at right-angle, that means KM ⟂ JL
and that simply means, if you get the slope of KM and the slope of JL, the product of their slope is -1
then multiply both slopes, if their product is -1, that means, they're perpendicular to each other, and it IS a rhombus only, then.