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3 years ago

How do you divide 100.5/1.5

Mathematics

2 answers:

aivan3 [116]3 years ago

7 0

Divide 100.5 by 1.5 to get 67.67

fenix001 [56]3 years ago

3 0

1.5/100.5=75 I think I'm not sure hopefully it's the answer your looking for

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(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ

quester [9]

Answer:

Step-by-step explanation:

Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.

On expanding the left hand side of the expression we have;

= (8x² −15x)−(x² −27x)

Open the paranthesis

= 8x² −15x−x²+27x

collect the like terms

= 8x²−x²+27x −15x

= 7x²+12x

Comparing the resulting expression with ax²+bx

7x²+12x = ax²+bx

7x² = ax²

a = 7

Also;

12x = bx

b =12

The value of b - a = 12 - 7

b -a = 5

Hence the value of b-a is equivalent to 5

3 0

3 years ago

Substitution:<br><br> y=6x+11<br><br>y-4x=15

german

Answer:

x=2

Step-by-step explanation:

6x+11-4x=15

2x+11=15

2x=4

x=2

4 0

3 years ago

What is the length of segment BC? A coordinate plane is shown. Point B is located at negative 3, negative 2, and point C is loca

Mrac [35]

The length of segment BC can be determined using the distance formula, wherein, d = sqrt[(X_2 - X_1)^2 + (Y_2 - Y_1)^2]. The variable d represent the distance between the two points while X_1, Y_1 and X_2, Y_2 represent points 1 and 2, respectively. Plugging in the coordinates of the points B(-3,-2) and C(0,2) into the equation, we get the length of segment BC equal to 5.

4 0

3 years ago

Read 2 more answers

Can someone help me find the value of x

tia_tia [17]

60 because all of the sides are equal

3 0

3 years ago

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If AD and BD are bisectors of CAB and CBA respectively. Find the sum of angles x and y.

olchik [2.2K]

The picture in the attached figure

step 1
we know that
It is given that AD and BD are bisectors of ∠CAB and ∠CBA respectively.
Therefore,
x = ∠CAB/2 -----> equation 1
y = ∠CBA/2 -----> equation 2

step 2
In triangle ABC,
∠CAB + ∠CBA + ∠ACB = 180° ----> [The sum of all three angles of a triangle is 180°]
∠CAB + ∠CBA + 110° = 180°
∠CAB + ∠CBA = 180° - 110°
∠CAB + ∠CBA = 70° ------> divide by 2 both sides
∠CAB/2 + ∠CBA/2 = 70/2 -------> equation 3
substitute equation 1 and equation 2 in equation 3
x+y=35

hence

the answer is
x+y =35°
⇒ x + y = 35° ...[From equation (1) and (2)]

5 0

4 years ago