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3 years ago

how can you determine if a relation represented as an equation is a function? explain your reasoning

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

8 0

Answer:

A relation is a function if x values never repeat, so every input will only have one output. If the function is graphed you can do the vertical line test, a relation passes if you can draw a vertical line anywhere on the graph and it only intersects with the relation once.

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I need help! do i subtract the 45-64? or add!?

Len [333]

Answer:

19°

Step-by-step explanation:

180-64=116

116+45=161

180-161=19

4 0

2 years ago

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Find the slope given points (3,2) (4,7)

snow_lady [41]

Answer: The slope is 5.

Step-by-step explanation: Use formula: (y2-y1)/(x2-x1)

(7-2)/(4-3)

5/1 = 5

Have a nice day! :)

6 0

2 years ago

A house is valued at $118,000.00. The homeowner decides to add on a two-car garage that increased the value of the home by 15%.H

nasty-shy [4]

Answer:

The value of the house after adding the garage is $135,700.

Step-by-step explanation:

Given,

value of house before adding garage = $118,200.00

we need to find the value of house after adding two car garage.

Solution,

Since after adding two car garage the value of the house increased by 15%.

So firstly we will find out the 15% of the value of the house after adding garage.

So we can say that;

15% of the value of the house after adding garage is equal to 15 divided by 100 the multiplied with the value of the house before adding garage.

15% of the value of the house after adding garage = $\frac{15}{100}\times118,000=\$17,700$

Now, The value of the house after adding garage is equal to the sum of value of house before adding garage and 15% of value of house before adding garage.

We can frame it in equation form as;

The value of the house after adding garage = $\$118,000+\$17,000=\$135,700$

Hence The value of the house after adding the garage is $135,700.

3 0

3 years ago

Alberto is making a budget. He owes a cell phone bill of $60 per month for 23 more months, plus the fees for any extra usage suc

Elena-2011 [213]

Answer:

Pretty sure it is C

Step-by-step explanation:

5 0

2 years ago

To play basketball with her friends, Evangeline needs to pump air in her ball, which is completely deflated. Before inflating it

Nadya [2.5K]

Answer:

ρ_air = 0.15544 kg/m^3

Step-by-step explanation:

Solution:-

- The deflated ball ( no air ) initially weighs:

m1 = 0.615 kg

- The air is pumped into the ball and weight again. The new reading of the ball's weight is:

m2 = 0.624 kg

- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.

m_air = Δm = m2 - m1

m_air = 0.624 - 0.615

m_air = 0.009 kg

- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:

V_air = 4*π*r^3 / 3

V_air = 4*π*0.24^3 / 3

V_air = 0.05790 m^3

- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:

ρ_air = m_air / V_air

ρ_air = 0.009 / 0.05790

Answer: ρ_air = 0.15544 kg/m^3

4 0

3 years ago

Read 2 more answers

how can you determine if a relation represented as an equation is a function? explain your reasoning​

how can you determine if a relation represented as an equation is a function? explain your reasoning