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Vitek1552 [10]
3 years ago
7

What is the length of the diagonal of a 10 foot by 8 foot rectangle?

Mathematics
1 answer:
zloy xaker [14]3 years ago
6 0
Diagonal of a rectangle formula:

Diagonal = √l² + w²
Diagonal = √10² + 8²
Diagonal = √100 + 64
Diagonal = √164
Diagonal = 12.806 feet.

Or you can use the pythagorean theorem. The diagonal of a rectangle is the hypotenuse of a triangle.

a² + b² = c² ; where a and b represents the lengths of the triangle and c is the hypothenuse. In this case, the lengths are 10 ft and 8ft.

10² + 8² = 100 + 64 = 164 ; This represents c².
c = √c² = √164 = 12.806 ft
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Answer:

a) Matrix B = \left[\begin{array}{c}5\\7\\9\end{array}\right]

b) Matrix AB = \left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right]

c) $12,695

Step-by-step explanation:

Matrix A = \left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right]

a) Matrix B = \left[\begin{array}{c}5\\7\\9\end{array}\right]

Gross Receipt = AB

\left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right] . \left[\begin{array}{c}5\\7\\9\end{array}\right] = \left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right]

c) Total revenue is the sum of receipts from 4 cinemas given in part b

Hence,

Total revenue = $2525 + $3620 + $2845 + $3705 = $12,695

3 0
3 years ago
Jacinta compares the volume of two boxes. Both boxes have a width of
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Answer:200 in ^3

Step-by-step explanation:

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2 years ago
suppose that $20,000 is invested at an interest rate of 3.2%. what would be the amount in the account in 5 years if invested
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Step-by-step explanation:

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3 years ago
M(-3,2) is the midpoint of AP. If A has coordinates (-1,5), what are the<br> coordinates of P?
Inessa05 [86]

Answer:

<h3>            P(-5, -1)</h3>

Step-by-step explanation:

If M is midpoint of AP then:  

x_P-x_M=x_M-x_A\qquad\quad\ \wedge\qquad y_P-y_M=y_M-y_A\\\\x_P-(-3)=-3-(-1)\qquad\wedge\qquad y_P-2=2-5\\\\x_P+3=-3+1\qquad\quad\ \wedge\qquad\quad y_P-2=-3\\\\x_P=-3+1-3\qquad\quad\ \wedge\qquad\quad y_P=-3+2\\\\x_P=-5\qquad\qquad\ \wedge\qquad\qquad y_P=-1

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3 years ago
A garage is drawn using a scale of 2 2/3 inch =6feet if the actual height is 68 ft what is the height of the garage
butalik [34]

Answer:

Step-by-step explanation:

The drawing of the garage is a smaller representation of the actual garage. A garage is drawn using a scale of 2 2/3 inch = 6feet. Let us first convert 2 2/3 inch to improper fraction. It becomes 8/3 inch.

Let us determine the unit measurement.

If 6feet = 8/3 inch,

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= 8/18 inches. Therefore

if the actual height is 68 ft , then, the height of the garage on the drawing will be

68 × 8/18 = 272/9 = 30 2/9 inches

3 0
3 years ago
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