A deer accelerates at a constant rate from 0 mph to 25 mph in 20 seconds. How far does the deer run during this time?
1 answer:
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Answer:
B) (-2, 5)
Step-by-step explanation:
Perhaps easiest is to try the points to see what works. You can also graph the equations or solve by any of several other means.
<u>Trying the points</u>
A) 3(-2)+4(-2) = -6 -8 = -14 ≠ 14
B) 3(-2) +4(5) = -6 +20 = 14; -2 = 2(5) -12 = 10 -12 . . . . true
C) 3(-4) +4(4) = -12 +16 = 4 ≠ 14
D) 3(2) +4(2) = 6 +8 = 14; 2(2) -12 = -8 ≠ -2
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Choice B ( -2, 5) is the only point that works in both equations.
Consider the attached figure. The height CD cuts the triangle exactly in half. This means that
Moreover, since CD is the height of the triangle, we know that ACD is a right triangle. We know the hypothenuse AC to be 20 feet because it is a side of the triangle, and we just found out that AD is 10. We can use the pythagorean theorem to deduce
So, the area is
