Find the solution to the quadratic equation 4y squared +26y+30=0

Mathematics

1 answer:

mrs_skeptik [129]4 years ago

3 0

4y² + 26y + 30 = 0
a = 4
b = 26
c = 30

y = [-26 +/- √(26)² - 4(4)(30)] / [2(4)]
y = [-26 +/- √676 - 480] / [8]
y = [-26 +/- √196] / [8]
y = [-26 +/- 14] / [8]

⇒ y = [-26 + 14] / [8]
y = [12] / [8]
y = 1.5

⇒y = [-26 - 14] / [8]
y = [-40] / [8]
y = -5

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3 years ago

Could someone confirm if I was correct or not?

Andrei [34K]

Correct! Excellent Job

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