What is the slope of the line through (-2,-6) and (2, 2)?

A zoo has a menagerie containing four pairs of different animals, one male and one female for each. The zookeeper wishes to feed

mixer [17]

Answer:

144

Step-by-step explanation:

We will use permutations to solve this problem

There are 4 pairs each having a male and a female.

The total number of sample points is 4! = 4*3*2*1= 24

He chooses the male first then the number of sample space he is left with are 3! = 3*2*1=6

The total number of ways he can select is 4! 3! = 24 * 6= 144

Another way of finding it out is

he has 4 pairs each having a male and a female so he chooses 1st male then he would choose from this

4 female choices*3 male choices * 3 female choices *2 male choices *2 female choices *1 male choices *1 female choices *= 4*3*3*2*2*1*1= 144

7 0

4 years ago

Find dy/dx for 4 - xy = y^3

storchak [24]

Answer:

$\frac{dy}{dx}=-\frac{y}{3y^2+x}$

Step-by-step explanation:

4-xy=y^3

dy/dx=?

$\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}$

Solving for dy/dx: Addind x dy/dx both sides of the equation:

$-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}$

Common factor dy/dx on the right side of the equation:

$-y=(3y^2+x)\frac{dy}{dx}$

Dividing both sides of the equation by 3y^2+x:

$\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}$

7 0

3 years ago

A teacher wants to assign 4 of the 15 practice problems at the end of the lesson. How many different assignments are possible?

zheka24 [161]

Answer:

15/4= 3.75

Step-by-step explanation:

3 0

3 years ago

F(x)=∣x∣

elixir [45]

Answer:

Step-by-step explanation:

There are two transformations, one vertical, one horizontal.

The + 9 part outside the absolute value sign moves the graph up 9 units.

Replacing x with x - 1 moves the graph right 1 unit.

<em>Comment:</em> The horizontal shifts sometimes appear backwards: x - 1 looks like a shift to the left, but it's not.

Example: f(4) = |4| = 4. To get the same output (4) from g(x), you have to use a value for x that is 1 unit <u>larger</u> than 4. g(5) = |5 - 1| = 4.

5 0

3 years ago

.

Nonamiya [84]

The only point outside of the line is (2, 0)

In order to find if a point is outside, inside or on the line, you simply have to put the number into the equation. If the result is both sides are equal, then it is on the line. If the left side is bigger than the right side, then it is outside of the line. If the right side is bigger than the left, then it is inside of the line. So lets plug in and see where (2, 0) falls.

(x - 2)^2 + (y + 3)^2 = 4

(2 - 2)^2 + (0 + 3)^2 = 4

0^2 + 3^2 = 4

0 + 9 = 4

9 = 4

Since the left side is bigger than the right, we know it is outside of the line.

3 0

4 years ago