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topjm [15]
3 years ago
14

Solve for the variable: 3.5x=32.2 What’s the variable?

Mathematics
1 answer:
kirill115 [55]3 years ago
4 0

Answer:

The variable is x.

The value of the variable is 9.2.

Step-by-step explanation:

The equation shows the variable x multiplied by 3.5 with the result of that multiplication being 32.2. In order to solve for x, you must "undo" that multiplication.

The definitions of the multiplicative inverse and of the multiplication identity element tell you how to do that. The multiplicative inverse of a number is its reciprocal: the multiplicative inverse of 3.5 is 1/3.5. Multiplying a number by its multiplicative inverse gives a result of 1. Here, that means ...

3.5 × (1/3.5) = 1

The property of the multiplicative identity element (1) is that anything multiplied by that is just that thing:

x · 1 = x

So, to solve this equation, you multiply both sides by the multiplicative inverse of 3.5:

3.5x = 32.2

(1/3.5)(3.5)x = (1/3.5)(32)

1x = 9.2 . . . . . carry out the multiplication

x = 9.2 . . . . . . recognize 1x = x

___

You will recognize that multiplying by 1/3.5 is the same as dividing by 3.5. In other words, we solve this equation by dividing it by the coefficient of x.

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kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

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< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




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3 years ago
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jenyasd209 [6]

Answer:

See below description.

Step-by-step explanation:

The function f(x) = x^4+x^3-2x^2 has the following characteristics:

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  • Zeros/roots: x=0, x=-2, amd x=1
  • Positive leading coefficient
  • Graph starts up, curves down through -2 on the x-axis and back up to 0 where it touches and curves down and back up again again. It comes down back through 1 and crosses.
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3 0
3 years ago
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Talja [164]

Answer:

Step-by-step explanation:

Given that :

Number of teams = 14

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Using the combination formula :

nCr = n! ÷ (n-r)! r!

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14C2 = 14! ÷ (12)! 2!

14C2 = (14 * 13) ÷ 2 * 1

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Hence, since they are going to be playing each other twice :

2(14C2)

2 * 91 = 182games

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nika2105 [10]

Answer:

The volume of the sandbox is 70 cubic feet

Step-by-step explanation:

To find the volume, simply multiply all of the dimensions by each other.

7ft * 5ft * 2ft = 70 ft^3

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