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pav-90 [236]
3 years ago
5

The function f(x) = 4(3)x represents the growth of a dragonfly population every year in a remote swamp. Erin wants to manipulate

the formula to an equivalent form that calculates four times a year, not just once a year. Which function is correct for Erin's purpose, and what is the new growth rate?
Mathematics
2 answers:
artcher [175]3 years ago
5 0
F(x)=4(3^(1/4))^4x ....131.6%
solmaris [256]3 years ago
5 0

Answer:

f(x)=4(1.32)^{4x}

New growth rate = 32%

Step-by-step explanation:

∵ The exponential growth function is,

f(x)=a(1+b)^x

Where,

a = initial value,

b = growth rate per period,

x = number of period,

Here, the given function that shows the population growth every year,

f(x)=4(3)^x=4(1+2)^x

By comparing,

Initial population, a = 4,

Let r be the rate per 4 times a year,

Thus, the function that shows the population growth four times a year,

f(x)=4(1+r)^{4x}

According to the question,

4(1+r)^{4x}=4(3)^x

(1+r)^x=3^x

Taking log  both sides,

x\log(1+r)=x\log3

\log(1+r)=\log3

By graphing calculator,

r=0.316=31.6\% \approx 32\%

Hence, the required function would be,

f(x)=4(1+0.32)^x=4(1.32)^x

And, rate per period is 32%.

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