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3 years ago

Help!!!!!!! Meeee plead I’ve already out this question down but nobody answers it:(

Mathematics

2 answers:

Arlecino [84]3 years ago

6 0

Answer: hold up, the answer is 4, 2, 9, and 7. Don't worry I help you to answer this question. Wrong answer the answer is 1. Y = 6

2. Y = 8

3. Y = 1

4. Y = 3

Step-by-step explanation:

lorasvet [3.4K]3 years ago

3 0

Answer:

1. Y = 6

2. Y = 8

3. Y = 1

4. Y = 3

Step-by-step explanation:

1. Y = -(-1) + 5 = 1 + 5 = 6

2. Y = -(-3) + 5 = 3 + 5 = 8

3. Y = -4 + 5 = 1

4. Y = -2 + 5 = 3

Hope this helps you!

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3 years ago

Natalie has 412 apples that she must package into bags. Each bag must hold 8 apples. Natalie divides 412 by 8 and gets an answer

worty [1.4K]

Answer:

Natalie has 4 apples left

Step-by-step explanation:

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3 years ago

Question 1<br> If the diameter of a circle is 5 meters, what is the circle's radius, in meters?

olga_2 [115]

Answer:

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Step-by-step explanation:

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2 years ago

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51 centimeters to 16 meters

Hitman42 [59]

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Step-by-step explanation:

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3 years ago

Find the values of the measures shown when each value in the data set increases by 25. Mean: 109 Median: 104 Mode: 96 Range: 45

Vikki [24]

Answer:

The new values are as follows:

Mean: 134

Median: 129

Mode: 121

Range=45

Standard Deviation=3.6

Step-by-step explanation:

When a k real number is added to all the elements of the dataset, the new measures of center (mean, median, and mode) are simply found by adding the value k to the previous values. Thus

$Mean_{new}=Mean_{old}+k$

Here $Mean_{old}$ is 109 and k is 25 thus

$Mean_{new}=Mean_{old}+k\\Mean_{new}=109+25\\Mean_{new}=134$

Similarly

$Median_{new}=Median_{old}+k$

Here $Median_{old}$ is 104 and k is 25 thus

$Median_{new}=Median_{old}+k\\Median_{new}=104+25\\Median_{new}=129$

Also

$Mode_{new}=Mode_{old}+k$

Here $Mode_{old}$ is 96 and k is 25 thus

$Mode_{new}=Mode_{old}+k\\Mode_{new}=96+25\\Mode_{new}=121$

When a k real number is added to all the elements of the dataset, the new measures of variation (range and standard deviation) remain the same thus.

$Range_{new}=Range_{old}\\Range_{new}=45$

Similarly

$Standard\ Deviation_{new}=Standard\ Deviation_{old}\\Standard\ Deviation_{new}=3.6$

So the new values of mean, median, mode, range, and standard deviation are 134, 129, 121, 45, and 3.6 respectively.

4 0

3 years ago