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Svet_ta [14]
3 years ago
13

The area of an artist's square canvas can hold 113 square inches of paint. What is the approximate length of one side of the can

vas? (Approximate to the nearest hundredth inch.)
Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0
Area of canvas= 113 square in
area of one side= 113/4=28.22
=28 square in
fomenos3 years ago
3 0

it would be 10.63 inches

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3 0
3 years ago
What is the y-coordinate of the solution for the system of equations? x−y=−11 y+7=−2x
ICE Princess25 [194]

Answer:

y= 5

Step-by-step explanation:

Given the system of equations:

x-y=-11

y+7=-2x

In order to find the y coordinate of the solution we must first find the solution to this system of equations. We first start by solving one of the given equations and then substitute the answer of that into the second equation and further solve to get the final answers.

x=y=-11

y+7=-2x

y+7=-2x

+ -7

y = -2x - 7

x - y = -11

y = -2x-7

x-(-2x-7)=-11

x--2x=x+2x=3x

3x+7=-11

-7

-11+-7=-18

3x=-18

\div3

-18\div3=-6

x=-6

y=-2x-7

y=(-2)(-6)-7

-2\times-6=12-7=5

y=5

Hope this helps.

7 0
2 years ago
Solve for the value of x by applying the definitions of complementary and supplementary angles
Tatiana [17]

9514 1404 393

Answer:

  x = 52

Step-by-step explanation:

The square corner symbol indicates the sum of the marked angles is 90°. (They are complementary.)

  (x +3)° +35° = 90°

  x° = 90° -38° = 52°

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4 0
3 years ago
The difference 5wx^2-2wx^2
marishachu [46]
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3 years ago
You are swinging a bucket in a circle at a velocity of 7.8 ft/s. The radius of the circle you are making is 1.25 ft. The acceler
Ksju [112]

Given that,

velocity, v = 7.8 ft/s

Radius, r = 1.25 ft

To find,

a. What is the acceleration of the bucket?

b. What is the velocity if the acceleration is 25 ft/sec²?

Solution,

(a) The centripetal acceleration is given by :

a=\dfrac{v^2}{r}

Put v = 7.8 ft/s and r = 1.25 ft

a=\dfrac{(7.8)^2}{1.25}\\\\=48.672\ ft/s^2

(b) Put a = 25 ft/s² to find velocity.

v=\sqrt{ar} \\\\v=\sqrt{25\times 1.25} \\\\v=5.59\ ft/s

Hence, this is the required solution.

7 0
3 years ago
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